Soln4 - EE411 Spring 2008 HW#4 Solution (Q1) 6.72 The...

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EE411 Spring 2008 HW#4 Solution (Q1) 6.72 The output of the first op amp is = i 1 v RC 1 vd t = = t o i 6 3 2 t 100 dt v 10 x 2 x 10 x 10 1 = - 50t = i o v RC 1 t = t o 6 3 dt ) t 50 ( 10 x 5 . 0 x 10 x 20 1 = 2500t 2 At t = 1.5ms, = = 6 2 o 10 x ) 5 . 1 ( 2500 v 5.625 mV (Q4) 7.54 (a) Before t = 0, i is obtained by current division or = + = ) 2 ( 4 4 4 ) t ( i A 1 After t = 0, [] τ + = t - e ) ( i ) 0 ( i ) ( i ) t ( i eq R L = τ , Ω = + = 7 12 || 4 4 R eq 2 1 7 5 . 3 = = τ 1 ) 0 ( i = , 7 6 ) 2 ( 3 4 3 ) 2 ( 12 || 4 4 12 || 4 ) ( i = + = + = t 2 - e 7 6 1 7 6 ) t ( i + = = ) t ( i () A e 6 7 1 2t -
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(b) Before t = 0, = + = 3 2 10 ) t ( i A 2 After t = 0, 5 . 4 2 || 6 3 R eq = + =
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Soln4 - EE411 Spring 2008 HW#4 Solution (Q1) 6.72 The...

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