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Unformatted text preview: In experiment 2, a qualitative experiment must be written to determine which compound is being formed from using the same reactants but a different ion of iron. In the first equation, iron (2+) reacts with copper sulfate to form copper and iron(II) sulfate; in the second equation, iron(3+) is reacted with copper sulfate to form copper and iron(III) sulfate. For the experiment 1g iron should be mixed with 2-2.5g copper sulfate. Iron should be the limiting reagent in the first equation, so if there is extra iron left from the reaction then iron(III) sulfate and copper are produced. If there is not any iron left from the reaction then iron(II) sulfate and copper are formed. When the experiment was performed, iron (1.01g) was reacted with copper sulfate (2.435g) in 100mL of water. There was no extra iron left, so iron(II) sulfate was the compound formed....
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This note was uploaded on 10/26/2009 for the course CHEM 1310 taught by Professor Cox during the Spring '08 term at Georgia Institute of Technology.
- Spring '08