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Unformatted text preview: Volume solid: 3.3- 3.0 + 3.3 - 3.5 + 3.3- 3.5 3 •100 = 23% Mass liquid: 8.865- 8.866 + 8.865 - 8.865 + 8.865 - 8.865 3 •100 = .43% Volume liquid: 0% Percent Error: Solid: 3.0- 2.99 3.0 •100 = 1.53% Liquid: .9003- 0.8865 .9003 •100 = 0.33% Conclusions: The unknown solid was determined to be Scandium. The silver-white color of the un-known solid matches the characteristics of the metal. The given density of Scandium is 3.0 g mL and the found density of unknown solid #4 was 2.99 g mL . The unknown liquid was determined to be ethyl acetate. It was a colorless liquid and smelled slightly like nail polish remover, both of which are characteristics of ethyl acet-ate. The given density of ethyl acetate is 0.9003 g mL and the found density of unknown liquid #2 was 0.8865 g mL . The relative average deviation was high for the volume of the solid, which is contributed to the displacement method used to find the volume since it is not accurate....
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This note was uploaded on 10/27/2009 for the course CHEM 207 at Cornell.