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Unformatted text preview: Find: Voltage o V . University of Wollongong School of Electrical, Computer and Telecommunications Engineering ECTE290 2 Analysis: Looking at the figure, we can immediately see that V 2 = V . Using nodal analysis: ( 1 4000 + 1 2000 + 1 6000 ) V 1 1 2000 11 = ( 1 6000 ) V 1 ( 1 12000 ) V o = Solving for V 1 and V o , V 1 = 6 V and V o = 12 V Chapter 8, Solution 44. Known quantities: Circuit in Figure P8.44. Find: The output voltage v o . Analysis: The circuit is a cascade of a noninverting opamp with an inverting opamp. Assuming ideal opamps, the inputoutput voltage gain is equal to the product of the single gains, therefore S S F S F v R R R R v + = 1 1 2 2 1...
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This note was uploaded on 10/27/2009 for the course ECTE 290 taught by Professor Zhengli during the Three '09 term at University of Wollongong, Australia.
 Three '09
 ZhengLi

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