Homework 10 Solutions

Homework 10 Solutions - Find Voltage o V University of...

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University of Wollongong School of Electrical, Computer and Telecommunications Engineering ECTE290 1 Homework 10a Q1 Inverting amplifier Vout=-(Rf/Rin)Vin=2 volts Q2 Non-inverting Amplifier Vout=(1+RF/Rin)/Vin=-2.2 volts Chapter 8, Solution 5. Known quantities: The circuit of Figure P8.5. Find: 1 V . Analysis: (a) Using nodal analysis we can see that in the circuit of Figure P8.5(a) 0 6 6 3 1 1 1 = + + g V V V V or 4 1 g V V = (b) For the circuit of Figure P8.5(b), g k k V V V = + 6 6 and the non-inverting terminal voltage is 2 6 g k V V = Since the circuit shown is a non-inverting amplifier with unity gain, the output voltage, 1 V , is equal to the non-inverting terminal voltage: 2 1 g V V = Chapter 8, Solution 7. Note: The +/- terminals of the op amp are inverted in Figure P8.7. Known quantities: The circuit of Figure P8.7.

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Unformatted text preview: Find: Voltage o V . University of Wollongong School of Electrical, Computer and Telecommunications Engineering ECTE290 2 Analysis: Looking at the figure, we can immediately see that V 2 = V . Using nodal analysis: ( 1 4000 + 1 2000 + 1 6000 ) V 1 − 1 2000 11 = − ( 1 6000 ) V 1 − ( 1 12000 ) V o = Solving for V 1 and V o , V 1 = 6 V and V o = − 12 V Chapter 8, Solution 44. Known quantities: Circuit in Figure P8.44. Find: The output voltage v o . Analysis: The circuit is a cascade of a noninverting op-amp with an inverting op-amp. Assuming ideal op-amps, the input-output voltage gain is equal to the product of the single gains, therefore S S F S F v R R R R v ⎟ ⎟ ⎠ ⎞ ⎜ ⎜ ⎝ ⎛ + − = 1 1 2 2 1...
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Homework 10 Solutions - Find Voltage o V University of...

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