Tutorial 6 - , L=2 H and C=1/6 F. Solution: Known...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
F i n a l M a r k : ECTE 290 Tut 6 Student Name: All questions 1 mark unless indicated. Total 10 Marks. 1. Given an inductance L=2 H and an angular frequency ω =50 determine the impedance Z L (j ω )= j100 . 2. Given a capacitance C=0.002 F and an angular frequency ω =1000 determine the impedance in polar form Z C (j )= 0.5 -90 o 3. Determine the impedance if the inductor and the capacitor are in parallel connection Z(j )=- j0.5025 4. For a capacitor the current leads the voltage by 90 o 5. (6 marks) Find the current i(t) given v(t)=12cos3t, R=4
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: , L=2 H and C=1/6 F. Solution: Known quantities: The values of the impedance and the voltage applied to the circuit. Find: The current in the circuit. Analysis: Assume clockwise currents: s rad 3 = , V 12 o S V = 2 1 j C j Z C = = , 6 j L j Z L = = 4 4 2 6 4 j j j Z total + = + = A 45 12 2 A 5 1 5 1 4 4 12 I o . . j . j = = + = , ( ) ( ) A 45 12 2 o t cos . t i = + C v(t R L i ( t )...
View Full Document

This note was uploaded on 10/27/2009 for the course ECTE 290 taught by Professor Zhengli during the Three '09 term at University of Wollongong, Australia.

Ask a homework question - tutors are online