practice_final_b_key

practice_final_b_key - Practice Final Exam —— Chem 26...

Info iconThis preview shows pages 1–9. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Practice Final Exam —— Chem 26 (B) Name E"”:£/,_\(’ ‘ éiyj 2 U. C. Davis is an Honor Institution Professor Kauzlarich Student I. D. T.A. POTENTIALLY USEFUL INFORMATION and a PERIODIC CHART are given on the last two pages of this exam. The 5'04 final exam is scheduled for Wednesday, June 16*“, (8:00—10:00 am). Strung-fie 1d ligands CN', CO N02“ cn 800 400 Nit—ij H10 620 430 ox OH“ F- SCN‘, CI" 580 / 490 Br" 5 60 Weakfield ligands Name Each multiple choice question is worth 5 points. Circle the BEST answer. Only ONE answer will be graded-41‘ two are circled-—the answer will be counted as WRONG! 1. What type of particle is captured and what type is emitted in the nucleosynthesis, 54 54 \Fe -—> Mn ? (a) Neutron capture and proton emission occurs. V 59756 4. Jpn .9 3‘4 Mm + X P A (b) Neutron capture and 0i particle emission. (c) Only neutron capture occurs (d) Neutron capture and positron emission occurs (e) Electron capture occurs and 0c particle emission. 2. What set of hybrid orbitals is used by C in CICN?? (a) 5P2 .. (b) dsp3 = Cr C 3M; (c) 5P3 H D @ sp (6) cfsp3 3. Given: 20493049) rate= k[03]2[02]" The overall order of the reaction is @‘21 A (b) 2 (c) 3 (d) -1 (e) O 4. How many protons, and neutron, respectively, are there in 128D (a) 128, 53 .23 (b) 53, 128 53> (c) 53,181 (385 fifimg E; (d) 75,53 _;:,.—_.—3# 5. How many unpaired electrons are predicted for [Mn(Ci$l)6]4“? & (‘9 0 » «it my inund- b 1 u i g) 2 d5 (FL/O WM“ . (d) 3 M r (e) 5 [IL LIL. ’L PS C D 10. Name Consider the following reaction: 2N20(g) --> 2N2(g) + 02(9) rate = k[N20] For an initial concentration of N20 of 0.50 M, calculate the concentration of N20 remaining after 3.0 min if k = 3.4 x10'3 5‘1. 0“) 0.27 M _ €453 (1:) 0.12 M [Alt _ CREE) —(%.4-><l65§l )C574é903 C . (d) 0.99 M ‘ O. 2‘7 M. (e) 0.54 M The decay constant for strontium—90 is 0.0247 years"1. How many grams of strontium—90 remain if 10.0 g decay for exactly 75 years? (a) 0.14 g (in) 0.00329 9 ((3 1.57 g (d) 0.20 g (e) 1.85 9 Which of the following is optically active? (a) CH3€HCH(CI) (b)(CH3)2C(NH2)COOH ti @CH3CH2CH(NH2)COOH L‘chfifc‘, — Mi’lz (d) NHzCHzCOOH Cwfi (e) C(CH3)4 How long will it take to deposit 0.00235 moles of gold by electrolysis of KAuCl4(aq) using a current of 0.214 amperes? (a) 106 min 3+ _ (b) 17.7 min A“ t 56 9 4% (c) 70.7 min 0,5 : 3E}: t z ((8,; (a) 53.0 min F 7‘1}: (e) 26.5 min - (0 002.337 316! £330 L/wzoi) o . liar Givem Mn04'(aq) + H*(aq) + C|'(aq) --> Mn2*(aq) + 02(9) + H200) = $1 Wq SEC; :32) mm If the coefficient of MnO4‘ in the balanced equation is 2, how many electrons are transferred in the reaction? 7 10 I ' ' LEE); 5 mm + 274nm + ice «‘7 3M?” + @Hzlq (c) 2 (d) 7 (e) 8 Name For The following quesTions, H is necessary To show all your work in order To obTain full crediT for a roblem 11.[20 poinTs possible] (a) Draw all The isomers for The square planar complex [PTBrCl(NH3)2] and idenTify Then as eiTher cis—, Trans—. Circle any opTical isomers. >- There are no (sprig) Er EH3 BOWES‘ PEN—Flt r Cl Br~l9lc “Cl lxllHj inj 05— +mfls ’ (b) Name and correchy draw any one of The five 3d orbiTals. Clearly label your aXes. Ola: die (M9 CLUE (c) Your lab parTner made up soluTions of The Two complexes, [CoF6]3' and [Co(en)3]3*. UnforTunaTely, he forgoT To label The beakers. One soluTion is yellow and The oTher appears blue. MaTch The complex To The color and explain your choice. (@5533? blue. Cu'nPLex; F is a max; field lgamd, smll Ac, absorbs i‘éd/oiangc) a) uni Ml 31% blue [Cogmkffi gallons color ; an "is a Snag/med‘lwn h‘ela l'EWUJ {NC}: A0, mosses blue/WUCJC/ wc: ml sag yellow. (d) WriTe an equaTion for The synThesis of 4—meThylpenTanal using any appropriaTe reagenTs. 9H3 (3 4"”?le pcwlmlal 2 CH3 '- CH 'Cl’lz’CHL’C' H 0'45 034 CH3 0 ,— fi ‘ _ ,\ A A 3 l ll CH?) "‘ Ll’ll CH2 — (.I/ "a Pd, L/l'l‘ZL/ll CAASW ,K H "WM-5’? Or emu oTher coww“ W03 4 12. Name [15 poinTs possible] The following elecTrochemical cell can be described by The unbalanced equaTion. Cr2072' (aq) + H+(aq) + I'(aq)--> Cr3+ (aq)+ I2(s)+ H200) A soluTion conTaining K26r207 and H2504 is in one beaker and a soluTion of KI is in anoTher. A salT bridge is used To join The beakers. The elecTrode in boTh rxn is a PT wire and They are connecTed wiTh wires Through a voleeTer To deTecT a currenT. (a)WriTe The balance half reacTions for The anode (you may leave K+ and 5042‘ ouT of The half reacTion). 21’ ——a 3:; +- .26 (b) WriTe The balance half rxn for The caThode (you may leave K+ and $02- ouT of The 1/2 rxn). + a 3' ,7 ’4” + @207 T be —-->2 .20“ + (7sz (c) WriTe The cell diagram. Name 13. [10 points possible] The following kinetic data were obtained for the reaction N02(9) + 03(9) --> N03(9) + 02(9) Initial concentration, mmol/L Initial Rater! mmol/L-s [NOZJO 0.21 [0310 0.70 1.39 12.5 _j Experiment 1 0.70 11.4 0.18 ? fl (a) Write the rate law for the reaction gm : KCNO;1 1:053 (b) What is the order of the reaction? no .2 Order (Jamal l . (c) From the data, determine the value of the rate constant. .e ; _r2_‘02_'._._. ; 11:4 ‘W‘KL:§_,- CNOs] C033 (6. sablfimmfi )2- lflz '- 49- 9 L/wwm; (d)Is the following mechanism consistent with the rate law? Explain. Step 1. 02 <==> 20 fast Step 2. 03 + NO 9N02 + 02 f051' Step 3. N02 + O 9 NO + 02 slow Name______________ 14. [10 poin’rs Total --each is worth 2 p’rs] Complete and balance The following reactions. (0) 60(5) + H2(g) 9 Cut (6) (b) 4M5) +B049) -> Jabb?) LS) (c) Mg(s) + Br‘2(|) —> M%Br2 CS) (d) N453 +5420» 2N105 +~ 5am. (e) 62(5) +2F2(9) -> 6674 Cs) 1 .10 poim‘s possible—-each is wor’rh 2 st] Name or' give The sTr‘uc’rur‘e for The follo ' g compo ds (a) CH3CH2C CH2CH3 E: '1 "'- CH3 0+5 CH5 } I, I (b) 2,3,9-Tr‘imeThyldecane H ~ ' to. ’ ., i 2 "Q'\2.”CH2.'CH2_* ’H 'CH3 (c) (CHsCH2)3N mew ‘_ ~ +4 \ /H (d) 3—phenylpro e H ‘ = C CH2 ” A \ " H/(V: \CHz (e) 2=CHCH(CH3)2 ‘ v \r i "‘ ' b A ' a ‘ Name 16.(10 points) Sodium-24 is used for monitoring blood circulation. The mass of a Sodium- 24 atom is 24 u. (a) If a 2.0 Mg sample of sodium-24 has an activity of 17.3 Ci, what is its decay constant and its half—life? ,‘lD adiva :7 (:l‘l. 5L1 (9b) 7 I l‘ /' b4><lO|5wO 5 5.4 >00 nuclei/5 _ _ e - l u 1 Us 3 N _ (;,D x VOL” ~ )( —~—W-~-~-t—"-"""'*“:‘““‘ AUfl \‘= 3L) woos Xiogtj>C 94a / ti : 5.0 X id mqui 41 : QEflIt‘l N 3 (9.4 >< id‘ mick”; [5 “mam.--” MW.) (b) What mass of a 2.0 Mg sample remains after 2.0 days? A S" ,, w : l m WEE ll 1 o‘ — CLio da§>C§-Odfl(g> : Q'U/xla ' Ci . Mass remaining: : . 2.)» “fl”, M,m-,.m-_,h,,,-_.___§> ‘ w Name POTENTIALLY USEFUL INFORMATION: Conversions: 1cou|omb = 1 ampere x' 1 second H = 1 kg-mZ-S'2 In x = 2.303 log x u = 1.6605 x 10'27 kg qu = 1 disintergr‘ation/s 10 = 3.7 x 1010 disinteration/s 1 year = 3.16 x107 5 1de = 8.64 x104 5 Constants: F = 96,500 C-mol-1 R : 8.314 J-moI-1~K-1 N : 6.022 x1023 moi-1 c = 3.0 x108 m/s ljoule =1 volt x 1 coulomb c = 2.998 x 108 m/s h = 6.625 x10’34j-s In x = 2.303 log x F = 96.485 kJ/V'mol R = 0.0821 L-atm-mol‘l-K‘l mass of an electron = 5.4858 x 104' u mass of a neutron : 1.0087 u mass of 1H = 1.0078 u Equations: E = mc2 Activity 2 kN m/mo = e‘kT [AL = woe“ [AJT = [A]o/(1+[A]ok’r) Ink 2 MA - Ea/(RT) |n(k'/k) = (Ea/R)(1/T - l/T) |n(N/No) = ‘(0.693/T1/2)1' EceH = Ered + on Eoceu = (RT/nF)an Ecell = Eocell - (RT/nF)|nQ ne = It/ F N/No = €46r ln[A}»r = |n[A]o — kt 1/[A]T = 1/[A]o + kt 1'1/2 = 0.693/k t = -5.73 x103yeors/ln2(|nN/No) AG = —nFE ...
View Full Document

Page1 / 9

practice_final_b_key - Practice Final Exam —— Chem 26...

This preview shows document pages 1 - 9. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online