practice 1

practice 1 - LasT Name FirsT Name ‘ E e , Lab Sec. # ;...

Info iconThis preview shows pages 1–12. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
Background image of page 11

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 12
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: LasT Name FirsT Name ‘ E e , Lab Sec. # ; TA: ; Lab day/Time: Andreas Toupadakis, Ph.D. Fall 2006 (Circle One) SecTion A EXAM 1 Insfrucfians: CLOSED BOOK EXAM! No books, noTes, or addiTionaI scrap paper are permiTTed. All informaTion required is conTained on The exam. Place all work in The space provided. If you require addiTional space, use The back of The exam. A scienTific calculaTor may be used (if H is a programmable calcuIaTor, iTs memory musT be cleared before The exam). This exam has 12 pages ToTal. (1) Read each quesTion carefully. (2) For ParTs I and II, There is no parTial crediT given and only answers marked on This cover page will be graded. (3) The lasT 3 pages co‘nTain a periodic Table and some useful informaTion. You may remove Them for easy access. (4) If you finish early, RECHECK YOUR ANSWERS! U.C. Davis is an Honor InsTiTuTion /36 Possible PoinTs # 1-12 # 13—21 # 22 (15 poinTs) # 23 (25 poinTs) (2 poinTs each) (4 poinTs each) ToTal Score (100) 13-21 fafa/ poi/77‘s: Name Exam 1 (Page 2 of 12) Part I: Multiple Choice, Concepts (2 points each) Select the best answer and enter your choice on the cover sheet - No partial credit 1. Choose the net redox reaction that occurs in the galvanic cell: Zn(s) I Zn+2(aq) l| Pb+2(aq) I Pb(s) Pb(s) + Zn(s) —> Pb+2(aq) + Zn+2(aq) + 4e‘ Pb(s) + Zn+2(aq) —» Pb+2(aq) + Zn(s) Pb+2(s) + Zn+2(s) —> Pb(s) + Zn(s) + 4 e‘ Pb+2(aq) + Zn(s) a Zn+2(aq) + Pb(s) Pb(s) + Zn(s) + 4 e‘ —> Pb+2(aq) + Zn+2(aq) W 0- O 9‘ P 2 Which element is biologically important in oxygen transport in mammals? a. Zn . Fe Se Cr Au p.100- 3. Choose the correct voltaic diagram for the reaction: mm + A9N03(aq) a A9(s) + M9(N03)2(aq) a. Ag(s) lAg(aq) ll M92+(aq) l Mg(s) b- M9(s) | Mgztll A9*(aq) l A9(s) c. M9(s) I M92+II Ago) I Ag+(aq) d. A9(aq) l Ag(s) || Mg(s) l M92+(aq) 6. mm | M92+(aq) ll A9*(aq) l MG) 4. If the voltage of an electrochemical cell is negative then the cell reaction is: a. nonspontaneous slow exothermic spontaneous none of these 0 9-!” CT 5. Choose the INCORRECT statement about transition elements. a. Coordination compounds are formed by coordinate covalent bonds. b The metal ions provide empty dorbitals. c. The ligand supplies the pair of electrons. do Colored compounds and colored solutions occur because of electronic transitions that occur within partially filled a’orbitals. e. Paramagnetism is due to paired electrons. Name Exam 1 (Page 3 of 12) 6. LisT The following in order of increasing aTomic radius: V, Sc, Fe, and Ti. 0. Fe<V<Ti<$c b. Sc<Ti<V<Fe c. Ti<V<Fe<Sc d. V<Fe<$c<Ti e. Fe<$c<Ti<V 7 The elecTron configuraTion of Fezl is: 0. [Ar] 3d6 b. [Ar] 4523014 c. [Ar]4524p4 d. [Ar14514p1 e. [Ar] 552 8‘ Which of The following chemical equaTions represenTs a disproporTionaTion reacTion? a. 2 Cu¢(aq) + H200) —> Cu(s) + Cu0(s) + 2H§(aq) 2 CrO42‘(aq) + 2 H+(aq) ——> Cr2072' TiCl4(l) + H200) —> Ti02(s) + HCl(g) Mn04‘(aq) + 5 vozkaq) + H200) a ankaq) + voz‘mq) + 2 H‘(aq) none of The above 0.9—9.0" 9‘ In The compound K4[Fe(CN)6], The oxidaTion sTaTe of iron and iTs coordinaTion number, respecTively, are: a. —4 and Ten b. O and Ten c. +4 and four d. +2 and six e. -4 and six 10. Which one of The following could be a chelaTing ligand? NH3 CH3—CH2—NH2 NHz—CHz-CHz-NHZ any meTal ion CN' .NF-‘LPP'P Name Exam 1 (Page 4 of 12) 11. What is the correct IUPAC name for K3[Co(NOZ)6] ? a. tripotassiumhexanitrocobalt(0) b. tripotassiumhexanitrocobalt(III) c. potassium hexanitrocobaltate(III) d. potassium hexanitrocobalt(III) e. none of the above 12. The [Fe(CN)6]3_ complex ion: a. exhibits square planar geometry is diamagnetic exhibits octahedral geometry has two unpaired electrons has four unpaired electrons 990.6 Name Exam 1 (Page 5 of 12) Part II: Multiple Choice, Short Calculations (4 points each) Select the best answer and enter your choice on the cover sheet - No partial credit 13. Is it possible to use Brz to oxidize silver at standard conditions? ll. 16' i Bum) -'> 18v'(oql E : H 0‘3 1Q3(9l .,__5 V1A6+Ccufl +213- 'Ogg -,.-~—~~--»-— 4 mam-m» o , g ‘ ’7'“ or v v Spomlomemys 3Ylal l. 2 Aaal "alg‘loqyl’ lee,» (C((( " 14. What is the concentration of Cu2+ in the following cell if the cell voltage is 0.955 V? Zn | Zn” (0.125 M) H of?) | Cu 0. 0.572M b. 1.08x10'2M , 1+ - c _ Z \-->/~ Z rm 6 7: +0.46 c. 1.58 x 10 6 M :1“ V‘ “m 0 d. 9.32x10'4M Cu (dq\ tie- __; Cum 6 : +o.%i‘ e 4.44 x10'4 M N~"\—-*\—/«~——~_M_wr --\ x4 6 "Lt 1+ Oven; €53 ZmCsl ‘4 (Q (uql‘Pngw Zv. (uq\ (05/: \.l \/ i~ c oos’q'z \ 4 l“‘(owi £041 3 €C((( ' T Wl’éV (Nu/UK A - _ 005‘ Oil 7 .,(. {WQS$ ': lil ~ ML €02) ————§— ”‘5 [Cullmseuo 2 [QB] 15. Given the following half—reactions occurring in the silver—zinc hearing aid battery, calculate the standard voltage of this battery. ZnO(s) + H200) + 2 e' a Zn(s) + 2 OH- E° = —1.260 v AggO(s) + H200) + 2 e‘ —» 2 Ag(s) + 2 0H" E° = +0.342 v . +1.602 v . +1.402V Owe \Au({’vxn mud» be Yevewed l. a b c. +0.858V \ c _ d. -O.858V WV‘C‘A Owe? Nest awe 6Q” >0 e . —1.602V The lat mm \s vcvayed ‘. O o 6 :tLlGOV 6 race; ‘0 . l— (efle ' I 6 : Name 16. 17. 18. Exam 1 (Page 6 of 12) A soluTion of AuCl3 is elecTr‘olyzed by passing 85.0 A of cur‘r‘enT for 17.6 min. WhaT mass of gold plaTes ouT? a. 61.39 g.\. _ ‘ _ c. 1839 3 d. 0.4839 (390 A : 539.0 E. E2116 mm ‘:l.(36)i|0g e. 2909 g ) 7 i x l v‘ e A ” A“ . 3 Au 1<8§o £)(I.ocxio s)( “we 0 ~> g gauged gwoflef U40(AL¢/ ’ 0'3 g) 044 Anal- CalculaTe The equilibrium consTanT for The reacTion: Fe(s) + Cd2+ (aq) a Fe2+ (aq) + Cd(s) 4O O. 1“, O V r b- :8 F681 "5 Fe cam He’ 6 :, ¥C.L\s c. d. 10 Ld‘l‘lwq» +1e' as» cdm 6 '2 --o.qo e. 50 O 001§¥ eiggalooc; V é («e/«e ‘: ' M zéu l/(-Cq e l ’ .023”? 0.0% : O '/€ul(2c‘ m l(€c‘ :S'O 2. The simplified equaTion for The reducTion of iron ore is: F6203(s) + 60(9) —> Fe(|) + 602(9) When iT is balanced, The coefficienTs are: Name Exam 1 (Page 7 of 12) 19. One mole of sodium hexacyanoferraTe(III) dissolves in waTer To give: a. 8 moles of ions. b. 2 moles of ions. c. 4 moles of ions. d. 5 moles of ions. e. 3 moles of ions. l'l’LOCZ) - I 3’ ‘ 9 3chlcoq3 l— FfiCCNle (dql l\l*33F€(.Cl\/lg CS\ 20. Given The sTandard reducTion poTenTials: Ag+ (aq) + e‘ —> Ag(s) E° = +0.80 V 2 H+(aq) + 2 e‘ —+ H2(9) E° = O V N03_(aq) + 4 H+ (aq) + 3 e_ —> NO(g) + 2 HzO(|) E° = +0.96 V C|2(g) + 2e_ —+ 2 C|_(aq) E° = +1.36 V Which of The following sTaTemenTs regarding The reacTiviTy of solid silver aT sTandard condiTions is True? a. Silver reacTs wiTh hydrogen gas. b. Silver does noT dissolve in niTric acid. c. Silver dissolves in hydrochloric acid. d. Silver dissolves in all acids. e. Silver dissolves in niTric acid. .. O 3A3csw we 3A6 Coufl + 3e 5 908W W 0310mm T Li Hl<oq\+%e’-—> NOCQT limoa) 6/:TOQC V Ne‘l” \(Xm l< gpom-lromeovq >C> 21. The complex [Fe(H20)(,]3+ absorbs lighT of wavelengTh 700. nm. The value of The ligand field sapliTTing (in kilojoules per mole) is: a. 1.71x10 kJ-mol’1 - ,_ ~ M4, b. 1.31x105kJ'mol’1 B : h-v -f c - \/~7\ Ag [3 -. ,3.” c. 8.45x108kJ-mol‘1 « 5 . ‘1 , '37 ' 8 -I 2' S'Ziiigetflil-l A : (awn-993:9. M > , 100.x10“‘5 vm 1.1,8Lixio j : 1.8L‘Xl0m21lflj Pev \OV‘. . . g . -‘ fin B75 ifiLiuol kjuwo-el \Moe 30mg Name Exam 1 (Page 8 of 12) _ ParT III: Long Answers Please show all work for calculations - ParTial crediT may be given 22. (15 poinTs) Consider The compound TeTracarbonyldichloroiron(II): a) WriTe iTs molecular formula. b) Draw iTs Two geomeTric isomers and label Them correchy as cis- and Trans—. NoTe: Assume ThaT The carbonyl group aTTaches iTself To The meTal via The carbon aTom. a) Molecular Formula: Fe ( C O) L‘ b) Cis—isomer Trans -isomer flame Exam 1 (Page 9 of 12) ___________________________._——————————— 23. fl 4" “\Ud e c (25 poinTs) A working galvanic cell is based on The following half-reacTions: Fe2*+2e_—>Fe E°=-O.44V MnO4- + 8 H+ + 5 e_ —+ an+ + 4 H20 E° = +1.51 V a) WhaT is The balanced cell r‘eacTion? b) WhaT is The cell poTenTiaI, E°ceu = .9 c) Wr‘iTe The line noTaTion. d) SkeTch The cell and show The direcTion of elecTr‘on flow, The correcT placemenT of The reading chemical species in each half cell and Their concenTraTions. e) DesignaTe The chemical idenTiTy of The anode and caThode and Their‘ sign (+ and -). a) The bfilanced cell reacTizn; :eéz > O SLFC ——5 Ve JrQe‘l 621.0.(H V 1 Emma; +Se’ +8H* 'amfi“ +qH1o] Q :L l.‘5ll/ SR: we; SR” Hoe’ u g 1+ _ . .- “~«"Vl~‘v09: ILA/MOM +loe'+ lélllfl') QIVM Tell“? (we: “95V ' , i. ’ 1+ 1+ 6% +1 W‘moc HOH 2»ch mix/m b) The cell poTenTial: E°Ce” : 4‘. L 0) g V c) The line noTaTion: +6) H'LO 1+ ~ Jr 1" C€(g) l (3 (can MWOL‘ “HRH CC‘QMMV‘ Cqu l Pl 0% d) and e) SkeTch The cell and show all The informaTion you are asked. Name Exam 1 (Page 10 of 12) Some useful equa’rions and cons’ran’rs: PLEASE NOTE: Imporfam‘ values and equations required for calcula’rions are given wifh The respective problem. The following may or may not be of any use. Cons’ran'rs: R : 8.3145 J / mol K F = 96,485 C/ mol e‘ NA = 6.022 x1023 R = 0.08206 L a’rm / mol K c = 2.998 x108 m / s h : 6.626 x10"34 J 5 1 nm :109 m Equafions: AG" 2 ~—nFE:,:,,, AG = —nFEce,, AG° = AH° — TAS" AG = AG° + RT an V0 0 0.0592 0 0.0257 A0 =—RThLKW Ew,=Ew”— ng EMl= anw l C l A : ch arge(C) = current (A)xtime (s) 1 mol e" = 96,485 C Azlzv czvl Name Exam 1 (Page 11 of 12) Reduction Half-Reaction (V) Mm’igw [32(1) + 2 e‘ ——> 2 F (aq) 2.87 Weaker “WNW; H202(aq) + 2 mm) + 2 e“ ——> 2 H200) 1.78 reducing -">%“”‘ MnOflnq) + 8H+(aq) + 5e- —> Mn2+(aq) + 4 H200) 1.51 agent C]2(g) + 2 e‘ ——-> 2 Cl'(aq) 1.36 Cr2072‘(aq) + 14 H+(aq) + 6 e‘ —~> 2 Cr3*(aq) + 7 H200) 1.33 020;) + 4 H+(aq) + 4 e‘ ——> 2 H200) 1.23 Br2(l) + 2 0‘ —9 2 Br'(aq) 1.09 Ag"(aq) + e‘ ———> Ag(s) 0.80 Fe7’*(aq) + e“ ——-—> Fcz*(aq) 0.77 02(g) + 2 H+(£l) + 2 e“ -—9 H202(aq) 0.70 5(5) + 2 e- ——> 2,1-(aq) 0.54 020;) + 2 H200) + 4 e” ——> 4 OH‘(nq) 0.40 Cu2*(nq) + 20' —-——> Cu(s) 0.34 —-> 5112*(114) Wm ker oxidizing agent Sn“(aq) + 20" I’bz+(aq) + 29' Ni3+(aq) + 20‘ Cd2*(aq) + 26‘ F92+(nq) + 2 e‘ Zn2"(aq) + 2 e" 2 H300) + 2 e‘ Ai3*(aq) + 3e‘ Mg2+(aq) + 20" Na“(uq) + e“ Li"(aq) + e“ ————> Pb(s) —-> Ni(s) ~—-> Cd(s) --> Fe(s) —-—> Zn(5) --—> Hzg) + 2 OH'(aq) ——> 141(8) —-> Mg(s) ~—-> Na(s) -—> Li(s) 0.15 m 3 2mg 53 :_ €5.02 EBEWWEEEE Eé N: mm a flag hm“ £232 ,vamo an 2T2: H8 335: bay/\BmmEb—Quméfivéusoérgénmtn 89c moEmZ we.»oam< 98 mummmE O<LDH 32 3mg ,sasmfi>m.w $8 8va $3 :5 a3 :3 Eé 58 $3 38 ES £32 Sgggmaaaaaapaa me Q: SH 2: 3 mm 8 3 8 a a No a 8 $3: :3: £332 3E £232 022 £832 8,5 $32 3.02 A2: «3: 8833 23: saafiaaaaaggaafi E on $ we $ 8 Q a. S S G 8 am wm Eu £5 38V Goa God God sou $8 :03 Ed 6va fig :2 m: :m mm 8 E 2 Q E N: E o: 2: we 2: 2: 2: 2: ow ww a £338 S8 334% $8” 38062 MERE 23% M22 SSE $2: $3.2: 2%: $8.me RE: 283: Mm 05 EL w: 5< E : m0 0% >9 «H (E 3 mm 8 mm NW ; a 2 w» R E K E E S S 3 mm 822 2;: 23: :2: $3.2: $2: $832 8.2: $3 38 338 EN: £83; 8.5 $8.3 am am E wU w< wm 5H 5m 0E 02 DZ HN > Hm am a 3 av Ms S 3 3 S Q S S 8 mm mm 2 3.3 $883 33.; 23.3 Sm? 2030.: $0.8 $3.3 on :2 HQ > CL om «U M 8 2 E a S a S a 32$ 28ng 34 “Z w: 0: fig 85 :89 cm 2 cm ow 3 g «.22 $332 OBS ox H 09 3 m S 33 v8.3 8% 853; GS $6 3% $20 «$me oommmmxm HM Hm om m< 00 «Q :N :0 00 mm mm «m mm mm : om a R $0.2 52m 83m 628,2 35.3 $2me H< 5 m m Mm 2 M: t S 2 E 2 NH 2 32.2” ‘ movwoowfi $3.2 «$00.: 85.2 :m‘o Nwfiflo‘o 3&6 02 m 0 Z O m mm 5 0— o w n o w v m Noomoo‘v «once; Ego.“ on I E N _ a $5805 o8 we 2%? Bwocom ...
View Full Document

This note was uploaded on 10/27/2009 for the course CHE 2C taught by Professor Enderle during the Winter '08 term at UC Davis.

Page1 / 12

practice 1 - LasT Name FirsT Name ‘ E e , Lab Sec. # ;...

This preview shows document pages 1 - 12. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online