Unformatted text preview: C (26 , 4) Â· C (26 , 5) = 983 , 411 , 000 ways. 2. Four cards are drawn at random without replacement from a standard deck of 52 cards. A) (5 pts) What is the probability of no ace? The probability of obtaining no aces at all = ( 48 4 ) ( 52 4 ) = 0 . 7187. B) (5 pts) What is the probability of at least one ace? The probability of obtaining at least one ace = 1Probability of obtaining no aces at all. So the probability of obtaining at least one ace = 1( 48 4 ) ( 52 4 ) = 0 . 2813....
View
Full
Document
This note was uploaded on 10/27/2009 for the course MATH 17C taught by Professor Lewis during the Spring '09 term at UC Davis.
 Spring '09
 Lewis
 Math

Click to edit the document details