08 112 ft 684 lbfft2 1200 there 008 100 602 04 2322

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Unformatted text preview: 4 C1 ln r C2 The constants are found from the two no-slip conditions u(r a) 0 1 2K a 4 C1 ln a C2 u(r b) 0 1 2K b 4 C1 ln b C2 The final solution for the velocity profile is u 1 4 d (p dx gz) a2 a2 b2 a ln ln (b/a) r r2 r=a u(r) r r=b x u(r) | v v Fig. 6.15 Fully developed flow through a concentric annulus. | e-Text Main Menu | Textbook Table of Contents | Study Guide (6.91) 6.6 Flow in Noncircular Ducts 363 The volume flow is given by a Q u2 r dr d (p dx 8 b gz) a4 b4 (a2 b2)2 ln (a/b) (6.92) The velocity profile u(r) resembles a parabola wrapped around in a circle to form a split doughnut, as in Fig. 6.15. The maximum velocity occurs at the radius a2 b2 2 ln (a/b) r 1/2 u umax (6.93) This maximum is closer to the inner radius but approaches the midpoint between cylinders as the clearance a b becomes small. Some numerical values are as follows: b a r a 0.01 b b 0.1 0.2 0.5 0.8 0.9 0.99 0.323 0.404 0.433 0.471 0.491 0.496 0.499 Also, as the clearance becomes small, the profile approaches a parabolic distribution, as if the flow were between two parallel plates [Eq. (4.143)]. It is confusing to base the friction factor...
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