Chapt06

# 643 the orifice has t the greatest loss and the

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ssary. We are given D 0.2 m and V1 2.0 m/s. The pipeapproach Reynolds number is thus ReD (2.0)(0.2) 1.02 10 6 V1D 392,000 For all three cases [(a) to (c)] the generalized formula (6.128) holds: V1 Vt 2( p1 p2) 1/2 Cd 2 where the given data are V1 2.0 m/s, 1000 kg/m3, and known values into Eq. (1) gives a relation between and : 2.0 1/2 2(50,000) 1000 2 ) p 2 or (1) 4 1/2 (1 50,000 Pa. Inserting these 0.2 (2) The unknowns are (or ) and Cd. Parts (a) to (c) depend upon the particular chart or formula needed for Cd fcn(ReD, ). We can make an initial guess 0.5 and iterate to convergence. Part (a) For the orifice with D: 1 D taps, use Eq. (6.132) or Fig. 6.40. The iterative sequence is 2 1 0.5, Cd1 0.604, 1 0.624, 0.566, Cd2 2 0.606, 0.640, 2 0.559 3 We have converged to three figures. The proper orifice diameter is d Part (b) D 112 mm Ans. (a) For the long-radius flow nozzle, use Eq. (6.134) or Fig. 6.41. The iterative sequence is 1 0.5, Cd1 0.9891, 1 1.022, 0.442, Cd2 2 0.9896, 2 1.009, 3 0.445 We have converged to three f...
View Full Document

## This note was uploaded on 10/27/2009 for the course MAE 101a taught by Professor Sakar during the Spring '08 term at UCSD.

Ask a homework question - tutors are online