Chapt06

# Chapt06

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Unformatted text preview: ants. If the flow rate is given, we can evaluate the right-hand side and hence the total head loss. If the head loss is given, a little iteration is needed, since f1, f2, and f3 all depend upon V1 through the Reynolds number. Begin by calculating f1, f2, and f3, assuming fully rough flow, and the solution for V1 will converge with one or two iterations. EES is ideal for this purpose. EXAMPLE 6.17 | v v Given is a three-pipe series system, as in Fig. 6.24a. The total pressure drop is pA Pa, and the elevation drop is zA zB 5 m. The pipe data are | e-Text Main Menu | Textbook Table of Contents | pB Study Guide 150,000 6.8 Multiple-Pipe Systems Pipe L, m d, cm , mm /d 1 2 3 100 150 80 8 6 4 0.24 0.12 0.20 377 0.003 0.002 0.005 The fluid is water, through the system. 1000 kg/m3 and 1.02 10 6 m2/s. Calculate the flow rate Q in m3/h Solution The total head loss across the system is pA hA→B pB zA g 150,000 1000(9.81) zB 5m 20.3 m From the continuity relation (6.105) the velocities are 2 d1 2 V1 d2 V2 and 16 V1 9 V2d2 Re1 V1d1...
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## This note was uploaded on 10/27/2009 for the course MAE 101a taught by Professor Sakar during the Spring '08 term at UCSD.

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