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Unformatted text preview: ,700. At Red Better f 0.0201, V
0.471/0.0201 4.84 m/s and Red
/d 0.0002, compute fnew 0.0201 [Eq. (6.64)]. 72,600. At Red 72,600 and We have converged to three significant figures. Thus our iterative solution is
V 4.84 m/s Q V 4 d2 (4.84) 4 (0.3)2 0.342 m3/s Ans. The iterative approach is straightforward and not too onerous, so it is routinely used by engineers. Obviously this repetitive procedure is ideal for a personal computer. Engineering Equation Solver (EES) Solution EES In EES, one simply enters the data and the appropriate equations, letting the software do the
rest. Correct units must of course be used. For the present example, the data could be entered
rho=950 nu=2E-5 d=0.3 L=100 epsod=0.0002 hf=8.0 g=9.81 | v v The appropriate equations are the Moody formula (6.64) plus the definitions of Reynolds num- | e-Text Main Menu | Textbook Table of Contents | Study Guide Chapter 6 Viscous Flow in Ducts
ber, volume flow rate as determined from velocity, and the Darcy head-loss formula (6.30):
Re V d/nu Q V pi d^2/4 f...
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- Spring '08