Chapt06

# Obviously this repetitive procedure is ideal for a

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Unformatted text preview: ( 2.0 log10(epsod/3.7 hf 2.51/Re/f^0.5))^( 2) f L/d V^2/2/g EES understands that “pi” represents 3.141593. Then hit “SOLVE” from the menu. If errors have been entered, EES will complain that the system cannot be solved and attempt to explain why. Otherwise, the software will iterate, and in this case EES prints the correct solution: Q=0.342 V=4.84 f=0.0201 Re=72585 The units are spelled out in a separate list as [m, kg, s, N]. This elegant approach to engineering problem-solving has one drawback, namely, that the user fails to check the solution for engineering viability. For example, are the data typed correctly? Is the Reynolds number turbulent? EXAMPLE 6.10 Work Moody’s problem (Example 6.6) backward, assuming that the head loss of 4.5 ft is known and the velocity (6.0 ft/s) is unknown. Direct Solution Find the parameter , and compute the Reynolds number from Eq. (6.66): gd3hf L2 Eq. (6.66): Red Then (32.2 ft/s2)(0.5 ft)3(4.5 ft) (200 ft)(1.1 E-5 ft2/s)2 [8(7.48 E8)]1/2 log Red d V 0.0008 3.7 7.48 E8 1.7...
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## This note was uploaded on 10/27/2009 for the course MAE 101a taught by Professor Sakar during the Spring '08 term at UCSD.

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