Chapt06

# The spacing is 2h 4h 04 ft the reynolds number is

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: the flow is laminar, since Re is less than 2300. You could use the laminar-flow friction factor, Eq. (6.83) flam 96 ReDh 96 1200 100 (6.0)2 0.4 2(32.2) v | | hf 0.08 and v from which p 1.9(32.2)(11.2) e-Text Main Menu | Textbook Table of Contents 0.08 11.2 ft 684 lbf/ft2 | 1200; there- Study Guide Ans. (b) 362 Chapter 6 Viscous Flow in Ducts Alternately you can finesse the Reynolds number and go directly to the appropriate laminar-flow formula, Eq. (6.79) h2 p 3L V or p 3(6.0 ft/s)[0.0038 slug/(ft s)](100 ft) (0.1 ft)2 and hf p g 684 slugs/(ft s2) 684 1.9(32.2) 684 lbf/ft2 11.2 ft This is one of those — perhaps unexpected — problems where the laminar friction is greater than the turbulent friction. Consider steady axial laminar flow in the annular space between two concentric cylinders, as in Fig. 6.15. There is no slip at the inner (r b) and outer radius (r a). For u u(r) only, the governing relation is Eq. (6.34) Flow through a Concentric Annulus du d r dr dr Kr K d (p dx gz) (6.90) Integrate this twice u 1 2K r...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online