Chapt10

# 19 in si units gives with n 1 10 2y2 y 2 0015 23 or 5

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: A 2y2 3.21 m2 A y b 2.53 m Ans. It is constructive to see what flow rate a half-hexagon and semicircle would carry for the same area of 3.214 m2. For the half-hexagon (HH), with 1/31/2 0.577, Eq. (10.25) predicts 2 yHH[2(1 A or yHH 1.362 m, whence Rh Q 0.5772)1/2 1 2 y 0.577] 2 1.732yHH 3.214 0.681 m. The half-hexagon flow rate is thus 1.0 (3.214)(0.681)2/3(0.001)1/2 0.015 5.25 m3/s or about 5 percent more than that for the rectangle. D2/8, or D 2.861 m, whence P For a semicircle, A 3.214 m2 Rh A/P 3.214/4.484 0.715 m. The semicircle flow rate will thus be Q 1.0 (3.214)(0.715)2/3(0.001)1/2 0.015 1 2 D 4.494 m and 5.42 m3/s or about 8 percent more than that of the rectangle and 3 percent more than that of the halfhexagon. 10.4 Specific Energy; Critical Depth As suggested by Bakhmeteff [13] in 1911, the specific energy E is a useful parameter in channel flow | v v E | e-Text Main Menu | y Textbook Table of Contents V2 2g | (10.28) Study Guide 672 Chapter 10 Open-Channel Flow where y is the water depth. It is seen from Fig. 10.8a that E is the height...
View Full Document

## This note was uploaded on 10/27/2009 for the course MAE 101a taught by Professor Sakar during the Spring '08 term at UCSD.

Ask a homework question - tutors are online