Chapt10

20 in fig 106b for a given n and slope s0 we may plot

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Unformatted text preview: x Qmax 0.718 2.129 n n 1/2 R2/3S0 at 128.73° and y (10.20) in Fig. 10.6b. 0.813D (10.21) 1/2 R8/3S0 at 151.21° and y 0.938D As shown in Fig. 10.6b, the maximum velocity is 14 percent more than the velocity when running full, and similarly the maximum discharge is 8 percent more. Since real pipes running nearly full tend to have somewhat unstable flow, these differences are not that significant. | v v 10.3 Efficient Uniform-Flow Channels | The simplicity of Manning’s formulation (10.19) enables us to analyze channel flows to determine the most efficient low-resistance sections for given conditions. The most common problem is that of maximizing Rh for a given flow area and discharge. Since Rh A/P, maximizing Rh for given A is the same as minimizing the wetted perimeter e-Text Main Menu | Textbook Table of Contents | Study Guide 670 Chapter 10 Open-Channel Flow αy α = cot θ y θ W Fig. 10.7 Geometry of a trapezoidal channel section. b P. There is no general solution for arbitrary cross sections, but an...
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