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Chapt10

# With h 01 m the specific energy levels must be e1 v2

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Unformatted text preview: gative) soThere are three real roots: y2 lution is physically impossible. The second (smaller) solution is the supercritical condition for 1.2 Subcritical bump 1.0 1 y1 = 1.0 m 2 y2 = 0.859 m 0.8 y 0.6 ∆ h = 0.1 m 0.612 m 0.451 m 0.4 0.90 Ec = 0.918 m 1.00 v | Supercritical 1.10 E2 = 1.015 m E10.6 v 676 1.20 E1 = 1.115 m E | e-Text Main Menu | Textbook Table of Contents | Study Guide 10.4 Specific Energy; Critical Depth 677 E2 and is not possible for this subcritical bump. The first solution is correct: y2(subcritical) 0.859 m Ans. (a) The surface level has dropped by y1 y2 h 1.0 0.859 0.1 0.041 m. The crest velocity is V2 V1y1/y2 1.745 m/s. The Froude number at the crest is Fr2 0.601. Flow downstream of the bump is subcritical. These flow conditions are shown in Fig. E10.6. Part (b) For critical flow in a wide channel, with q E2,min Ec 3 yc 2 3 2 q2 g 1.5 m2/s, from Eq. (10.31), Vy 1/3 (1.5 m2/s)2 9.81 m/s2 3 2 1/3 0.918 m Therefore the maximum height for frictionless flow over this particula...
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