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ET 352Week 1 AssignmentAmplitude Modulation FundamentalsGrantham University
Written Assignment: HW1 - Amplitude Modulation FundamentalsWork Chapter 3 Problems 2, 6, 10, 12, 16 pg. 1152: An AM wave displayed on an oscilloscope has values of Vmax = 4.8 and Vmin = 2.5 as read from the graticule. What is the percentage of modulation?6: What is the mathematical relationship of the carrier and modulating signal voltages when overmodulation occurs?In 10: What is the total power supplied by an AM transmitter with a carrier power of 2500 W and modulation of 77 percent?Pt = Pc (1+m^2/2(Pt = 2500W (1+ (0.85^2/2))Pt = 2500W (1.36125) = 3403.125W = 3403W12: An AM transmitter puts a carrier of 6 A into an antenna whose resistance is 52V. The transmitter is modulated by 60 percent. What is the total output power?
Pt = Pc(1+(m^2/2))It = Ic √(1=(m^2/2)) = It = 6A √(1+(0.6^2/2)It = 6A * 1.086278049120022 = 6.517668A = 6.52AR = 52V/6.52A = 7.98ΩPt = It^2RPt = 6.52^2A * 7.98Ω = 339.04W16: The peak-to-peak output voltage of 675 V appears across a 52-Vantenna on voice peaks in an SSB transmitter. What is the output PEP?Vrms = (Vp-p/2) * 0.707 Vrms = (675V/2) * 0.707 = 238.6125 = 238.61VPEP = Vrms^2 / RPEP = 238.61^2V /52PEP = 1094.8986W = 1095W