Sample Solutions and Exam Statistics

Sample Solutions and Exam Statistics - l Lt @ Var-<3 S...

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Unformatted text preview: l Lt @ Var-<3 S dcuq EECS 314 // Winter 2005 // Exam 1 // Questions SCUM SCI—me 63 A. m. Thursday February 3, 2005, 9:30 — 11:00 AM Students will take exam in the following rooms, according to the first letter of their last names: 220 Chrysler Auditorium (our lecture room) —- A through L 1504 G.G.Brown (Lee Iacocea Lecture Hall) -— M through S 1303 EECS -— T through Z Students whose doctors recommend “1V2 time” on the exam will take it in 2246 EECS. Instructor: Alexander Ganago Exam rules Under the Honor Code do NOT discuss this exam With an bd until 5 pm. Friday February 4, 2005 l. The exam costs 50 points and includes two groups of multiple-choice questions. Questions 1 through 10 are 2 points each; questions 11 through 20 are 3 points each. 2. You will be given 80 minutes to work on the exam (besides the time you need to fill in your name and UM ID number on the answer sheet). If you have a class right after the exam, plan to arrive early for an earlier start. 3. You must sign the attendance form before you take the exam. 4. The answers to the exam should be written on the standard sheet for multiple-choice questions provided by the University of Michigan. 5. Bring your calculators, good 23 pencils and erasers! 6. The exam will be graded automatically; the scanning machine will evaluate your answers based on the darkest spots on your answer sheet. If you believe your answer sheet gets so dirty that the machine might misread your answers please ask your instructor for a blank sheet. Note that the machine cannot accept “double answers” such as “A and E.” 7. This exam booklet lists all questions and provides workspace. You may keep it for reference. If you need more workspace, ask your instructor for extra pages. 8. Calculators are allowed. 9 PDA, cell phones, and laptop/notebook computers are not allowed on the exams. 10. Books and notebooks are NOT allowed. One “cheat sheet” of standard size 8.5xl 1” is allowed (with notes made on both sides). 11. Hand in your exam to your instructor. Do NOT leave until your instructor makes a written note certifying the receipt of your answer sheet. Abide by the Engineering Honor Code: “I have neither given our received any aid on this exam, nor have I concealed any violation of the Honor Code.” Alexander Ganago Page 1 out)” January 21 ~ 28, 2005 ll Version 3 41 EECS 314 ll Winter 2005 ll Exam 1 ll Questions soxwfh answers/A. Gama: a Section One: 2-point questions 1 The essence of Kirchhoff s voltage law is that A. The electric c . - - 'n the Universe are conserved C. The relationship between current ough a circuit element and voltage across that element is linear for certain materials D. The difference of currents leaving a particular node in the circuit is zero E. The difference of voltages across any element in a particular circuit is zero 2 The essence of Kirchhofi’s current law is that A. The electric chares in the Universe are conserv - B. There exist electric charges of two types, called negative and positive C. The direction of current shown on the circuit diagrams is opposite to the direction, in which the electrons actually move D. The difference of currents leaving a particular node in the circuit is zero E. The difference of voltages across elements in a particular circuit is zero 3 (Contributed by Robert Bai) Consider an ideal voltmeter and an ideal ammeter. Which statement is true? A. Both the voltmeter and ammeter should have infinite resistance B. Both the voltmeter and ammeter should have zero resistance C. They both should have finite resistances. D. The voltmeter should have zero resistance; the ammeter should have infinite resistance E. e voltmeter should have infinite resistance; the ammeter should have zero resistance Alexander Ganago Page 2 of January 21 — 28, 2005 1/ Version 3 M. EECS 314 // Winter 2005 // Exam 1 // Questions 4 Sotth seaming/A (image, (Based on the idea contributed by Robert Bai) In a DC circuit, the current I through resistor R and voltage V across the resistor determine the power P that the resistor dissipates. Which of the following formulas are correct? A. Only (a) and (b) B. Only (0) and (d) C. 0111 e and 13- Only (D 5 (Contributed by Robert Bai) In the circuit shown on this diagram, the unknown resistance R equals . . . A. 10052 B. 125 Q 1 kg D. 4 k9 + / E. 8 kg 10 \ R - 2 V Alexander Ganago Page 3 0170/ January 21 — 28, 2005 // Version 3 .41 EECS 314 // Winter 2005 // Exam 1 // Questions Sawfly. answer; amok swam; 6 To “kill” an independent source 2 L Gama o A. Replace it with a short circuit B. Replace it with an open circuit . ‘ ep ace a voltage source W1 a short circuit but replace a current source with = I I en circuit 1). Replace a current source with a short circuit but replace a voltage source with an open circuit E. The correct strategy depends on the other sources in the circuit. \ 7 (Contributed by James Kim, with a modification) What is the energy required to move 10 coulombs of charge through 120 volts? 2‘3???“ lo a a» 120 U = 3.0.8333] 1114401 : WsSeC w to A~Sec * 8 (Contributed by Phil Choi) Voltage polarity and the conventional current direction are as denoted. Which statement is correct? A. P = I ' V, for I > O and V < 0, the source absorbs power. B. P = I - V, for I > 0 and V < 0, the source supplies power. i C. P = -—I - V, for I <0 and V < 0, the source supplies power. D. P = —-I - V , for I < 0 and V > 0, the source absorbs power. E. P = —I- V, for I > 0 and V < 0, the source supplies power. 9 (Contributed by James Kim) Which statement is wrong? A. Voltage division shows that voltage is divided among series resistors in direct proportion to their resistances. B. Current division shows that the current divides among parallel resistors in inverse proportion to the resistance paths. C. Series and parallel resistances can be combined by directly summing the series resistances and by summin the conductance of resistances in arallel. D. or a 5 mt circuit, e resistance is infinite, the current is zero, an the short circuits is determined b .l - rest of the circuit. E. Kirchhofi’s voltage law states that the sum of the voltage around any loop is zero. Alexander Ganago Page 4 of Jae/January 21 —— 31, 2005 1/ Version 3.1 11 EECS 314 // Winter 2005 // Exam 1 // Questions gown/yea SW 10 The Volt—Amp characteristic of a certain +k€ f circuit element is shown on the sketch. Vanna. v a P Pay-ck. Judging by the sketch, the element is . . . A. Ohmic B. Non-ohmic, with resistance that first increases and then decreases, as the voltage is increased C. Non-ohmic, with resistance that first decreases and then increases, as the voltae is increased D. Non-ohmic, with resistance that increases, as the voltage is increased E. on-o C, W! re51 - ce l a ecreases, ast evo tage lS mcrease. ACCOr 'Kj {27 @g‘H/L Mtl/Lt‘étObtf ‘Hu. «Ware-wk “5‘5 4"“ d resistance, resistance inc ma res fiNuh 1 2 3 4 Current.mA restsfaucz J and dim. digested: ' ‘HALS wmaw‘t is non—Ohumc. ' fiance B .HA 44,4 appeared r6545 (5:2 +1“ shot-cl 61/304129 ad U __ w auguw'tial reséstauc'e 12:11 Voltage, V increases anus. 1 2 3 4 Current, mA Continued on the next page Alexander Ganago Page 5 of )( January 21 — 31, 2005 // Version 3.1 M44. EECS 314 7/ Winter 2005 ll Exam 1 1/ Questions Sam/922. SW / A . m Section Two: 3-point questions 1 1 In the circuit shown on this diagram, the voltage VX equals A. -120 V B. 120v m C. 160V D. 280V 4A 0 7A Mesh Curram'ts 10S} 6,124.4 ‘ 2—74 Vx:Qi 41),. 4on = (4A —(—7A))«40J>. 12 In the circuit shown on this diagram, the currentI equals (3: 0:25 A D. 0.4 A E. None of the above. 1430.1 A Alexander Ganago Page 6 of 143/ January 21 — 31, 2005 // Version 3.1 d. 1 EECS 314 // Winter 2005 ll Exam 1 // Questions 13 SOUMPQQ SOQUt-COMS In the circuit shown on this diagram, the Thevenin equivalent voltage equals 4:35:- & 5m 109 C. 7.712V D. 4.5 V E. 3.724V 27V 9 VT : Vofqu CtT'CUL‘L'l" Tl/LMS‘ 1:20 (Du/LA UO’QJECLaQ dIVt'SIOH appflaes GAAFI'M gee—US ‘H’W'D‘jl‘ SOJL M 40JL T‘eSt'S'E'O‘T)’ 4 ._ UT: 27Vn_____————-40fi‘ :27V" g— 4.2V JL-e-‘l-OJL so ‘Vrp = U l 14 In the circuit shown on this diagram, the maximal power is 10 Q transferred to the load resistor RLOAD, which equals B. 109 15V 9 c. 409 Rmsn D. 50 Q E. None of the above. FOI- mime power trans‘pa‘“) ‘ g R LOA} =7 RTueumin 61* Tex-Mt 4’ Appfia Souréa +raug-Formaitou Q— JL ‘ .m: 0L g Alexander Gana o Page 70f waianuary 21 ~31, 2005 // Version'3.1 J This :5 one. a? mauj wags to sou/2 U: EECS 314 // Winter 2005 // Exam 1 ll Questions Gauag Q n 6 15 Sawing sW/A. In the circuit shown on this diagram, the Norton equivalent current equals . . . A. 12 A B. 8A D. 2 A E. 1.333 A. s ce +raks¥o our to 5094/42 mamj WG-55 ‘3' 3.17. 6J2. v v 42 3J16n' ” 36 CE 6 rmmtfou 0.. J1. wig ., 16 In the circuit shown on this diagram, the Thevenirl equivalent voltage at the terminals a, 1) equals B. 8V C. 6V D. 2V E. Zero. Alexander Ganago M Page 8 ofyo’ January 21 — 31, 2005 1/ Version 3.1 S EECS 314 // Winter 2005 ll Exam 1 // Questions Swab MS a 17 am (1,22 /A ‘ CS‘Q <13 Q (Contributed by James Kim) In the circuit shown on this diagram, what 2 Q is the equivalent resistance at the a . 12 9 terminals a, b ‘2' 4 9 x A.59 b 69 m 49 . t D. 20 Q E. None of the above. eausn=2JL an. 12nllC4JL+2JU=4JL tan. QJL+4JL+4JL=iOJL 6.). 6 4m. 18 In the circuit shown on this diagram, the voltage source V3 and resistance RS serve as a simple RS a model of an audio amplifier, which transfers the maximal power of 16 W to an 4—52 speaker VS RLOAD connected to the terminals (1, b as the load resistance RLOAD . 5 Suppose you do not have an 4-9 speaker at hand and connect a 8-9 speaker to the terminals :1, b as the new load resistance RLOAD . What is the power transferred to this new load? P awu #0 V‘ A. 16 W .— R was: - 4 J7- 2: $1213 w means“ +0uaizt Rs =4JL ‘m E - Yia =L6w E. None of the above. U ' Huts V5 = 4-6 v is u 9 RE 83 - 45v _ 4G... _ L: - A— 1.333A + J}. 1’2 _ .- 4JL 8 B: Lz‘en:4¢h22;“ P—chZZLU Alexander Ganago Page 90f 13’ January 21 ~31, 2005 // Version 3.1 11 EECS 314 // Winter 2005 // Exam 1 // Questions 19 Samaria 5W /H.6‘ahago In the circuit shown on this diagram, the Thevenin equivalent resistance at the terminals :1, b equals A. 501:9 B. 22 1:9 I! D 62 k9 K a u E: 27.68 kg S 0““? S ' .20th. 40 4.0km. kJL lira. 40kJLuLOkJL = 6 Lu; 20 This circuit is a simple model of a transistor amplifier. Assume that the resistors are fixed. If the current gain K of the dependent source can vary but remains positive (K >0), then the gain V0/ V3 of the amplifier circuit A. Remains constant, independent of K B. Remains negative, and decreases in magnitude as K increases C. Remains positive, and decreases in magnitude as K increases D. Remains positive, and increases in magnitude as K increases E. Remains negative, and increases in magnitude as K increases Alexander Ganago Page 10 of W January 21 —- 31, 2005 // Version 3.1 11 S EECS 314 ll Winter 2005 // Exam 1 // Questions own 5 W'm. 20 Pee /Q ' on This circuit is a simple model of a transistor amplifier. Assume that the resistors are fixed. If the current gain K of the dependent source can vary but remains positive (K >0), then the gain V0/ V3 of the amplifier circuit ... A. Remains constant, independent of K B. Remains negative, and decreases in magnitude as K increases C. Remains positive, and decreases in magnitude as K increases D. Remains positive, and increases in magnitude as K increases E. Remains negative, and increases in magnitude as increases Mesh mrrw$ Me- Show“ 4.170119. Liz}: L1: -K‘1 Va '-= {-2393 = " K'I'R3 W mesh: ________________ -V5+1eR1+CK+i)'I'RZ-=O t'ERuCKMD'Rzl-‘Vs :- LEW - R‘t-Qc-t-QJ'RZ Thu: v . Va "' 5 Ri+CK+L).R2 Va _ __ Rg-K __ __ 3.1—” -—-.. -— a +5: v5 R1+(K+L)'Rz Ru f; ’- Tke 303m is negative; [finial 3W”; “5 1" 6"ng Alexander Ganago Page)0’ of )5 January 21 —- 28, 2005 f/ Version 3 44 14 Evaluations and Examinations Office University of Michigan FREQUENCY, OVERALL EXAM SCORING RESULTS February a. 2005 instmflor: GANAGO Course: Electrical Engin & Comp Sci 314 Standard Scare Frequency Percentile Score 50 B 98 657 48 7 94 632 47 11 89 619 46 4 85 607 45 1 1 80 594 44 7 75 531 43 7 72 569 42 10 67 556 41 5 63 543 40 1 1 58 531 39 10 52 518 38 9 47 506 37 6 43 493 36 8 39 480 35 15 33 468 34 3 28 455 33 7 25 442 32 5 22 430 31 1 20 41 7 30 3 1 9 404 29 3 17 392 28 4 1 5 379 27 2 14 367 26 7 1 1 354 25 4 8 341 24 5 B 329 23 1 4 31 6 22 2 3 303 21 1 2 291 20 2 2 278 1 6 1 1 228 13 1 1 190 OVERALL TEST STATISTICS: Number of respondents: 181 Highest score: 50 Average score: 37 Standard deviation: 7.91 Lowest score: 13 Median: 39 13“? 12 Evaluations and Examinations Office University of Michigan ITEM ANALYSIS EXAM SCORING RESULTS February 3. 2005 Instructor: GANAGO Course: Etectrical Engin 8- Comp Key: 1 W Item Response Distribution “A: NUMbGr Percent Correct Discrimination Item A B C D E BLK ' A B C D E BLK " Responses Index 1 36 109‘ 1 3 32 0 0 20 60' 1 2 18 0 O 60 0.29 2 78“ 1 2 97 3 o o 43' 1 1 54 2 o o 43 0-28 3 o a 1 10 167' o o o 2 1 6 92 ' o o 92 0‘20 4 0 0 2 176' 3 0 0 0 0 1 97“ 2 0 0 97 '0-02 5 O 2 171' 6 1 1 0 0 1 94 ’ 3 1 1 0 94 0.30 6 3 1 1 69' 8 0 o 0 2 1 93 ' 4 0 o 0 93 0.23 7 6 1 8 1 165* 0 0 3 1 4 1 91 ‘ 0 0 91 0.22 s 21 97* 5 27 31 o o 12 54* 3 15 17 o o 54 0-29 9 0 5 19 150* 7 0 0 0 3 10 83’ 4 0 0 83 0.27 10 o 3 5 151' 22 o o o 2 3 83‘ 12 o 0 B3 0-14 11 6 9 4 1 161' o o 3 5 2 1 89 ' o o 89 0'21 12 162' 4 2 8 5 0 0 90" 2 1 4 3 0 0 9D 0-05 13 17 150' 2 1 10 1 Ci 9 83‘ 1 1 6 1 0 83 0.37 14 154* 0 B 15 6 0 0 85‘ 0 3 B 3 D 0 85 0.25 15 12 1 158‘ 7 3 0 0 7 1 87" 4 2 0 0 87 0.26 16 1213* 18 19 14 a 1 o 71 ' 9 1o 8 2 1 o 71 0-35 17 5 107' 18 0 51 0 O 3 59" 1O 0 26 D 0 59 0-40 18 8 80 2 34‘ 7 0 0 4 44 1 46" 4 0 0 46 0.43 19 5 11 140* 22 3 0 o 3 s 77' 12 2 o 0 77 0-59 20 3 15 9 87 67" O 0 2 B 5 48 37 ‘ 0 0 37 0-17 Keyed: 4 4 4 4 4 0 G 20 20 20 20 20 0 0 Number of respondents for the key: 181 Number of respondents overali: 181 Average number right 1or key: 15.1 Average number right overall: 15.0 Standard deviation for key: 3.03 Standard deviation overall: 3.00 quQL’S ...
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This note was uploaded on 10/28/2009 for the course EECS 314 taught by Professor Ganago during the Winter '07 term at University of Michigan.

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Sample Solutions and Exam Statistics - l Lt @ Var-<3 S...

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