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Aersp_311_Exam_I_08

# Aersp_311_Exam_I_08 - Aerospace Engineering 311 Exam I...

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Unformatted text preview: Aerospace Engineering 311 Exam I 9/25/08 Problem 1 — Multiple Choicegst (5 Points) Select the most accurate ending(s). The intermolecular force that allows spiders to walk on water, a steel needle to ﬂoat when placed gently in a pan of water and water “heads” on your freshly waxed car is known as b) Newtonian c) vorticity d) viscosity e) density 0 Brungart Problem 2 - Short Answer (10 Points) Explain the basic diﬁerences between the Eulerian and Lagrangian description of ﬂuid flow. BAUER. 366W3P‘L‘lom— Ob6¢W65 Hue. Mo'LlaDI‘b 3+0 DEE¢L£JPaPéILI¢5 ad: H16?! MOVE. ﬁbrcugh a at: HELA 6Pam. or- PO ' rub» (5 Pomﬁl . ' __ w ' b I 5;}; H36 heft. a. Lagranalari. clasu‘tp‘lzlom .ﬂngws iron»; cilia: abilwegand chasm becl ab 14: Moves gpaca- (5 Petra?) Problem 3 [11 Points) An aircraft ﬂies at a velocity of 67 m/s where the temperature is 15.6“C and the pressure is 1 atm. (a) What is the Mach number of the flow? (5 Points) M = 3% <3 Pom) Davin. c.10- mam. _. VIM/5 / H - :: am, 2 P .4145) germ/5 “ o (b) Assuming that the Mach number is 0.56, is the ﬂow about the aircraft considered to be compressible or incompressible? Why? (6 Points) Emgmz-c. M 5:03 - InCDMPFBGSIIDIE- (4 pomﬁ) M >05 - wnpresslbie. (H: 0-56) 7 0-3 s" COHPmsibiL (2 Ronnie») Problem 4 (9 Points) A barrel 1 m in diameter and containing an unknown liquid 2.0 m deep is exposed to that atmosphere at sea level. The pressure at the bottom of the barrel is 125,721 Pa. Determine the density of the unknown liquid. Hgérob-iza-L'Ic. rials-1:101. p= Pa - 63 E ('5 Fin-Lian) - o=-€31 %=I0li¢P& P P P F __ __ o- e - a? Zn : M ( F 4,43 9 (9.6062) ‘3 ‘3' i =12572IP2. a= 1.2m lash-t3 (:Po.q4:\ Problem 5 [40 Points Total} A layer of water ﬂows down an. inclined ﬁxed surface with the velocity proﬁle shown below. (a) Determine the magnitude and direction of the shearing stress that the water exerts on the ﬁxed Surface for U = 3 mis and h = 0.1 m. (10 Points) 7;: (2 Ennis) /Z:N__: ﬂoured. 7:0 5 IN: ace “m (I at.) In cin: o-izﬂow (I Pt.) (b) Determine the mass ﬂux through a plane normal to the ﬁxed surface for U = 3 mls and h = 0.1 m. Assume that the ﬂow extends a distance of l to into the page (i.e., z-dir.). (15 Points) 9-,: Jam- U%)A% (333.4145) Ewe—WI; f1: l‘i‘tbksla (l ﬁning Problem 5 Continued (40 Point‘s Total! (c) Determine the momentum ﬂux through a plane normal to the ﬁxed surface for U = 3 nuts and h = 0.1 m. Assume that the ﬂow extends a distance of 1 m into the page (i.e., z-dir.). (15 Points) ‘15:: {Lam-mas (1 mt) h i z z 4 a. ‘6 ““‘§%§— 4% +4%% 8 Pow—*3) Z : 0.533631% §\$K5M4f<Q1MX|Q l; “1: km N: Lam = 478.719 (1 Bauer) § 5 52 25 Problem 5( Points Total! Expand g:- into the x, y and z coordinate directions for a general velocity ﬁeld. In other words, determine the acceleration vector for the general velocity ﬁeld given below. ii = 110:, y, z, 01' + v(x. y, z, 0}" + w(x, y, z, 075 D; _ “ a —- -=~ Bil-— fin (u-vw (lRmn-E) 6 =A§+ﬁ+k§z (1'6: (Lu-L‘ﬂ‘r W12.) (£3? “51% + DIE cm * _.... T=E£+CU°§7W :AEE+U£+\J%+W%1+AEE+U%+V£+w%1 (Z Bowl?) 40" cal-rem! J—ﬂrm.) Useful Material For Exam 1 g m pdV 41,96 oﬁdS = 0 S g = 9.81 We2 13: jpmz? ofi)dS S 'l'lhln A3 hope-Lina of a . . m m M Cm Liquidsall ﬁlm that! gig/If mtg/(mm) Y.N/nl‘ p, N/In’ N/m‘ pal-m0 “mm” mm as my 2.13 3-2 mom-s —. ms Bum: 881 HI 3-4 1383-1 “3134-4 1.4 3+9 4.34 mm 1.990 9.6734 1733-3 LEE-Ht 955 3+! 4.45 My. . __ -- __ __ m _ 1103-3 2233-2 5.? 3+3 9.0 3+! 5.1! Elma: 5mm __l.llf{_u_114 up; w 4343-2 1.: 5+1 - 11.1 Finn 12 1.337 1623-4 — -— -- 1.16 (hauling 680 an 3-4 2.16 3-2 5.51344 9.53 3+8 3.68 (“slain - 1.2m m 6.33 5-2 :4 3-2 4343+, 23.0 m 50‘ 1.92 3-3 13 34 3." 3+3 1.6 3+9 5.56 — My ' ‘ '7 ‘- 13.590 :1.“ 3-3 43‘ 3-] M 3-3 2.55 3+“) 1.0? Mahmud 791 5383-4 2253-2 l343+4 8.3 3+8 4.63 SAE 1W all 810 m4 B-l‘ 3.6 3-2 — 13134-9 15.“! 8A3 10W all 876 1.7 3-1‘ — — — 14.0 SAEIIWGII _ _ \$1 2.9 51* 3.5 3-2 — 1.38 3+9 18.3 SABiGWdl 9a: 3.6 34‘ — - — 20.: Vista 998 1.1:: 3-3 723 3-2 2343+! 2.19 3+9 TINSAJ Sammy) 1M 1313-3 7.” 3-2 2343+! 2333+9 7.28 ...
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