{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

exam 1 spring 2002 - TABLE OF INTEGRALS dx(x(x(x(x(x(x 2 a...

Info icon This preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
TABLE OF INTEGRALS ( 29 ( 29 2 2 1/ 2 2 2 ln dx x x a x a = + + + ( 29 3/ 2 2 2 2 2 2 dx x a x a x a = + + ( 29 3/ 2 2 2 2 2 1 x dx x a x a - = + + ( 29 2 2 1/ 2 2 2 x dx x a x a = + + ( 29 ( 29 2 2 2 3/ 2 2 2 2 2 ln x dx x x x a x a x a - = + + + + + ( 29 ( 29 2 2 2 2 2 2 1/ 2 2 2 ln 2 2 x dx x x a a x x a x a + = - + + + ( 29 ( 29 3/ 2 5/ 2 2 2 2 2 1 5 x x a dx x a + = + ( 29 ( 29 ( 29 3/ 2 2 2 2 2 2 3/ 2 2 2 4 2 2 3 3 ln 4 8 8 x x a a x x a x a dx a x x a + + + = + + + + 1
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
TABLE OF COORDINATE SYSTEM FORMULAS cos x ρ φ = ˆ ˆ sin cos / x r θ φ = = r x sin y ρ φ = ˆ ˆ sin sin / y r θ φ = = r y z z = ˆ ˆ cos / z r θ = = r z sin cos x r θ φ = sin sin y r θ φ = cos z r θ = 2 2 x y ρ = + ( 29 1 tan / y x φ - = z z = sin r ρ θ = cos z r θ = φ φ = 2 2 2 r x y z = + + ( 29 1 2 2 2 cos / z x y z θ - = + + ( 29 1 tan / y x φ - = 2 2 r z ρ = + ( 29 1 tan / z θ ρ - = φ φ = 2
Image of page 2
Problem 1 (25 pts) A point charge having q = 1 [C] is at the origin. Find the vector force on this point charge due to a line segment of uniform charge density 0 l ρ [C/m] that is parallel to the x axis as shown below.
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern