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midx2.w09.sol.sec1

midx2.w09.sol.sec1 - ACTSC 433 WINTER 2009(SECTION 1...

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A id s : T i m e: Ex a min e r: ACTSC 433 - WINTER 2009 (SECTION 1) MID-TERM EXAM #2 - MARCH 10 2009 S\ k ~ ~ \c .. l~\v . . ~ c~ N A M E : _ Ca l c ul ato r 1 ho ur J o hnn y S.H. L i Qu e stion - Max i mu m Ma rk 1 10 - _. - 2 1 2 3 8 - - - _ . - - - - - - - - - - 4 10 - - To t a l 40 - -
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1 . Y ou a r e give n : i d i X i U i 1 0 2 . 0 - 2 0 - 2. 3 3 0 2 . 5 - 4 0 - 2 : 5 5 0 - 2: 5 6 0 2 . 6 - 7 0 - 3 , 0 8 2 . 3 3 . 2 - 9 2.5 - 3. 2 10 2 . 6 - 3 . 3 ( a ) C a lc u la t e t h e r i s k s et for e ac h d ea t h p oint . [4 m a rk s ] . { f 11 ) 1' 4t U 1 ~ *t J\~ ~- l 1 - ' .) 4 - ~ 3 1 \ : 2 2 - S 3 ~ ; ) . ( , \ 3 2 - l ~ 3 \ Lt - \ 4 - 3 .. 1 \ 0 \ \ 3 / \ ~ , '' ' "' I " -~
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:= 0.04 - 03:) ( c) Constru c t a 90 % symmetric lin e ar conf i denc e interval for 5 ( 3 . 1 ) . [ 2marks]
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( i ) T h ere i s no left - t run cat i o n. (i i ) There are fi ve d eat h po in ts . ( iii ) The fo ll ow in g s u mmary abo u t the d a t a: . I J Yj rj Sj 1 3 2 0 1 0 2 6 1 0 4 3 9 5 2 4 11 3 1 5 15 2 2 (a) F ind the n u m b e r of ri g ht- ce n sored o b servatio n s d u r i ng t h e fo ll ow in g ti m e i nte r vals : (i) 3::; t < 6 ; ( i i) 6: : ; t < 9; [4marks] K J o~ ~ " \ (~ f j= ' j-I - rk e . .. re . ~ ~ e .. . J ( 1 ) ~ ~~tz~/ .: tr d - r t~"'t-Ce , , - . . ~J . o bs e . No . ~~ _ _: i t I I I ( ~ ~_ . t: 3 ~ . U-, . (6 - t J ..e- e. . 1 ~ £ ' '0 J ~~- ~I ' \CL~ tu , ,,/ tl \ .. e - I\ ~ _ \- (t t L h ( ~ s . . ~. j . s -l ~ \ A , < - j ) ) - = 2CJ - co- ( 0 - = - 0 f -- Cf ~ ~ ) Re v- - ( , ~ b~ , /' ~ J - ~~-<: . ~~ j C\ls . ~"O\ ~-\I ' ~ ~ l ( J - 4 - -S::: :: t ( -
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\J ~ LA llOJ - ~ :: : f ; ~ T T t J2 + i2 . . - ==- O- l4~ ( 1- Gtb )(J O .. l4S '\ ~ l · II = 0< - f \ .. ( _ 2> ) - .. l ~S~~ q (0 l:J ~~"" e l Cl ~ I-Ie /0) : CJ - ,L3uJ -;:. . (0.\3 : tl . / .1_ 3 0 6d .- ')
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To mode l the data set above , y o u cons i d e r a dist r ib u tio n w i t h t h e fo ll owing p r obabilit y
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