Answer key to thermodynamics problems-part 2

# Answer key to - ∆ H=-11kJ Total q=-2.3kJ w=9.1kJ ∆ E=11.4kJ ∆ H=19kJ Pathway 2 step 3 q=6.84kJ w=0kJ ∆ E=6.84kJ ∆ H=11.40 step 4 q=7.6kJ

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Answer key to thermodynamics problems-part two Answer key to thermodynamics problems-part two 1. 2. 3. 19 in text; q= 30.9 kJ; w=-12.4 kJ; E=18.5kJ 4. 21 in text; -37.56 kJ 5. 29 in text; Pathway 1, step 1: q=30.4kJ, w=-13.8kJ, E=18.2kJ, H=30.4kJ; step 2: q=-28.1kJ, w=21.3kJ, E=-6.8kJ,

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Unformatted text preview: ∆ H=-11kJ Total q=-2.3kJ, w=9.1kJ, ∆ E=11.4kJ, ∆ H=19kJ Pathway 2, step 3: q=6.84kJ, w=0kJ, ∆ E=6.84kJ, ∆ H=11.40; step 4: q=7.6kJ, w=-3.0kJ, ∆ E=4.6kJ, ∆ H=7.6kJ Total q=14.4kJ, w=-3.0kJ, ∆ E=11.4kJ, ∆ H=19.0kJ 6. 7. 8. 9. 10. 11. 9. 10. 11. 12....
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## This note was uploaded on 10/31/2009 for the course CH 56435 taught by Professor Flowers during the Spring '08 term at University of Texas at Austin.

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Answer key to - ∆ H=-11kJ Total q=-2.3kJ w=9.1kJ ∆ E=11.4kJ ∆ H=19kJ Pathway 2 step 3 q=6.84kJ w=0kJ ∆ E=6.84kJ ∆ H=11.40 step 4 q=7.6kJ

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