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Unformatted text preview: Problem 3.2 Apply nodal analysis to determine V x in the circuit of Fig. P3.2. 1 2 4 2 3 A V x V + _ Figure P3.2: Circuit for Problem 3.2. Solution: At node V , application of KCL gives V 2 + 1 3 + V 2 + 4 = , which leads to V = 6 V . By voltage division, V x = V 4 2 + 4 = 6 4 6 = 4 V . Problem 3.3 Use nodal analysis to determine the current I x and amount of power supplied by the voltage source in the circuit of Fig. P3.3. 2 4 8 40 V 9 A I x V + _ I Figure P3.3: Circuit for Problem 3.3. Solution: At node V , application of KCL gives 9 + V 2 + V 4 + V 40 8 = V parenleftbigg 1 2 + 1 4 + 1 8 parenrightbigg = 9 + 40 8 7 V 8 = 9 + 5 V = 16 V . The current I x is then given by I x = V 4 = 16 4 = 4 A . To find the power supplied by the 40V source, we need to first find the current I flowing into its positive terminal, I = V 40 8 = 16 40 8 = 3 A . Hence, P = V I = 40 ( 3 ) = 120 W (The minus sign confirms that the voltage source is a supplier of power.) Problem 3.4 For the circuit in Fig. P3.4: (a) Apply nodal analysis to find node voltages V 1 and V 2 . (b) Determine the voltage V R and current I ....
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 '08
 Staff
 Volt, Fig, Thévenin's theorem, Current Source, Voltage drop

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