ch26questions - Clicker Session Capacitors and Dielectrics...

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Clicker Session – Capacitors and Dielectrics
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Capacitor C 1 is connected across a battery of 5 V . An identical capacitor C 2 is connected across a battery of 10 V . Which one has the most charge? 1) C 1 2) C 2 3) both have the same charge 4) it depends on other factors +Q –Q ConcepTest 25.1 Capacitors
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Since Q = C V and the two capacitors are identical, the one that is connected to the greater voltage has the most charge , which is C 2 in this case. Capacitor C 1 is connected across a battery of 5 V . An identical capacitor C 2 is connected across a battery of 10 V . Which one has the most charge? 1) C 1 2) C 2 3) both have the same charge 4) it depends on other factors +Q –Q ConcepTest 25.1 Capacitors
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1) increase the area of the plates 2) decrease separation between the plates 3) decrease the area of the plates 4) either (1) or (2) 5) either (2) or (3) What must be done to a capacitor in order to increase the amount of charge it can hold (for a constant voltage)? +Q –Q ConcepTest 25.2a Varying Capacitance I
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Since Q = C V , in order to increase the charge that a capacitor can hold at constant voltage, one has to increase its capacitance . Since the capacitance is given by , that can be done by either increasing A or decreasing d . 1) increase the area of the plates 2) decrease separation between the plates 3) decrease the area of the plates 4) either (1) or (2) 5) either (2) or (3) d A C 0 ε = What must be done to a capacitor in order to increase the amount of charge it can hold (for a constant voltage)? +Q –Q ConcepTest 25.2a Varying Capacitance I
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+Q –Q A parallel-plate capacitor initially has a voltage of 400 V and stays connected to the battery . If the plate spacing is now doubled, what happens? 1) the voltage decreases 2) the voltage increases 3) the charge decreases 4) the charge increases 5) both voltage and charge change ConcepTest 25.2b Varying Capacitance II
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Since the battery stays connected, the voltage must remain constant ! Since when the spacing d is doubled, the capacitance C is halved. And since Q = C V , that means the charge must decrease .
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This note was uploaded on 11/01/2009 for the course PHY phy2049 taught by Professor Wilfredngwa during the Fall '09 term at University of Central Florida.

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ch26questions - Clicker Session Capacitors and Dielectrics...

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