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Unformatted text preview: Problem 7 For this problem, you have to consider the times it takes the first bit of the first packet to be packetized, sent and transmitted over the network to the receiver. First, the bit has to wait until the first packet of 48 Bytes has been created completely by the encoder with a bit rate of 64 kbps. The time to do that is calculated as t enc = bits in packet encoder bit rate = 48 · 8 b 64 · 10 3 bps = 6 msec. (1) Now the packet has to be put on the link, which has a bandwidth of 1Mbps, which requires t link = bits in packet link bit rate = 48 · 8 b 10 6 bps = 3 . 84 μsec. (2) The packet requires t prop = 2 msec propagation delay until it reaches the receiver. The total delay thus is calculated as t enc + t link + t prop = 6 msec + 3 . 84 μsec + 2 msec = 8 . 384 msec. (3) 1 Problem 8 a As given by circuit switching, the bandwidth is (in this case equally) distributed amongst the users. Thus, 10 users can be supported....
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This note was uploaded on 11/01/2009 for the course EEE 459 taught by Professor Martinreisslein during the Spring '09 term at ASU.
- Spring '09