Problem_5-9 - =tan-1 (46/66+38.6) = 23.7 1 2 3...

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50° 66’ Determine P if  Moment of P about point A is 4000 lf-ft and length of bar is 60’ A P
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50° 66’ A P Line of action of P d d is shortest distance from line of action to point A M P|A = Pd=4000 lb-ft Need to find d
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50° 66’ A d M P|A = Pd=4000 lb-ft Need to find d 60’ =60cos(50°)=38.6’ =60sin (50°)=46’
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Unformatted text preview: =tan-1 (46/66+38.6) = 23.7 1 2 3 d=66*sin(23.7)=26.56 4 50 66 A P d M P|A = Pd=4000 lb-ft d=26.56 P=4000 lb-ft/26.56 ft P=150.6 lb 50 66 A P d M P|A = Pd=4000 lb-ft P=150.4 lb 90-23.7 =66.3 M P|A = [-Psin(66.3)]*46+[Pcos(66.3)]*(38.6) 38.6 46 ALTERNATIVE...
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Problem_5-9 - =tan-1 (46/66+38.6) = 23.7 1 2 3...

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