hw1 - thx,t:suu3/o Ari/MA 1;wa v 34 A m(9‘41 ’— mm 15...

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Unformatted text preview: thx,t:suu3): /o Ari/MA) 1/;wa v ( +34%) : A m (9‘41) \ ’—\ mm 15 The nag)“ or an ocsan wave is dzscfiberlby m: manna» y(z,l) z 1.55in(0.51»0.h) (m). Determine me phas: velocity and me wnvclengm and than sketch nyJ) n; : 21 mdsenngefiumx:0lox=2k Solution: The given wm may 1:: mfillcn as a cosine mam: y(x,x)=1.5cos(o.5x » 0.5x— n/Z). By oomparimn of [his wave with Eq. (1.32). y(x,x)=Acos(m—bz+¢o), ’ ‘ueaaimem m=2nf=o.5nd/s, B:%=0.6ndlm, _m 05 2x 21: 0.33 m, A ~ — 10-47 m- B Egan: P15: Pint of y(xJ) versus 3:. $1M} -D.'6x) {m}, with the argumcnt of the Pmblun 1.7 We Waves on n smug m gm“ by the following filnminns: mm nor-t) cosaur — 30x) (cm), 3:95am + 301) mm), What I is m cendmslcrs. The waves at: said to inlexftr: constructively when their supu'posiu'on ml : \y, + m is a maximum and they inlcrfem deszmenvety whtn m1 is a minimum (a) What at: me dxmuons uf pmpngnuon of wavcs mm and mm? (b) An = (ii/50) s, a. whal lacation x do me two waves intuch cunsuucuvaly, and what is the mnespondmg value of w? (n) Al 1 = (15/50) 5, at what locauon x do the two waves interfexe desuucuvely. and whmis me conesponmng valuc of [ym Sclution: ‘ I (I) Nam) is Inveling in posxl‘ive x-dlmclmn. mm) IS mvelmg m nean x—dilecxiun. 35?;‘5 EMEJ‘E] sinfiflx = 1.9 5in3flx. lfiim = 1-9 E Problem 1.11 Sivan two waves characterized by :91“): ficosflr, 3.13“) = fisin[ur+30°j, does ygfl} lead or lag 3.21“), and by what phase. angle? Solution: We: need to empress yzfir] in tenns of a. cosine: function: 3220‘) 2 fisinfil + SD”) = 6:05 — m: — 30”) = 6cos(fifl° — mt) =ficns{flI—60”}. fiance. yzm lags gum} by 60°. 5. w _ , 4‘56 W Vsine‘a ML WW rad/g 0 I ELK H n” MUN WWW”) . : my?” 5 ‘ H 174/: V firm“? Wk t» W. Wm“) WM lewd] : (L571’5f1M/3t 40'), 6;; Lag-e79 45% szbmzwm 3:?) v 51‘ i = Map/09”” A i¢)2/p£u5[wt+§§dp) A A) i; (5‘)). [A] : anew”. 1“); g. m {as ("m/MAW g) 1 w} m); a :2 LM ) _, .9;wa (A! M; m [pu‘lu‘ “idem __—\ human I.“ A m nu: Emu .3 cm m . gum-tar wxm . mm W) = mama/Hm. m wmam. mevuluguluupaqlun'unm \rxms durum .m. x,l.,c, m4 VA!) {5) Olmm m cmmmmuomm equnu‘un m Solve magma“ mova .n expmssmn (m maphmrcunzmi x L I M) figure m 748 RLC alum m ‘ .1 1 (I) V-(’)=RI+LE+E/idt. w Vow/3 MVQZNS a) l=k+im~1/mc) R+j(mL—l/u£‘) : mwmzbcil)‘ ...
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This note was uploaded on 11/02/2009 for the course EEC 130A taught by Professor Pham during the Spring '08 term at UC Davis.

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hw1 - thx,t:suu3/o Ari/MA 1;wa v 34 A m(9‘41 ’— mm 15...

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