hw11sol - H omework #11 solution outlines SOL-4. (a) Ksp =...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
3.091 Fall Term 2004 Homework #11 solution outlines SOL-4. (a) K sp = [Ba 2+ ] [CrO 4 2– ] (b) K sp = [Ca 2+ ] [CO 3 2– ] (c) K sp = [Pb 2+ ] [F ] 2 (d) K sp = [Ag + ] 2 [S 2– ] SOL-8. If [Hg 2 2+ ] = C s then [Cl ] = 2 C s K sp = [Hg 2 2+ ] [Cl ] 2 = [C s ] [2 C s ] 2 = 4 C s 3 Answer (c) SOL-10. Let C s = [Pb 2+ ] for PbSO 4 1.6 × 10 –8 = C s 2 C s = 1.3 × 10 –4 mol L for PbI 2 7.1 × 10 –9 = 4 C s 3 C s = 1.2 × 10 –3 mol L Lead (II) iodide is more soluble. SOL-16. the lithium carbonate dissolves according to Li 2 CO 3 = 2 Li + + CO 3 2– which by stoichiometry gives [Li+] = 2 [CO 3 2– ] = 2 c s , where cs means the concentration of solute or solubility of lithium carbonate for this reaction K sp = [Li + ] 2 [CO 3 2– ] = 4 c s 3 23 s 1.36 g Li CO 1 mol Li CO 1000 0.184 M = c 100 mL water 73.89 g Li CO 1 L mL ×= = K sp = 2.49 × 10 –2 NOTE: By definition, molarity means moles of solute per liter of solution. In this instance we have taken 100 mL water to be 100 mL of solution. Stricly speaking, this is not correct, but the difference between the two is small enough to allow the approximation. SOL-26. (b). The presence of fluoride ion from NaF represses the solubility of MgF 2 . This is an example of the common ion effect in action.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 11/02/2009 for the course CHEMISTRY 3.091 taught by Professor Donsadoway during the Fall '04 term at MIT.

Page1 / 4

hw11sol - H omework #11 solution outlines SOL-4. (a) Ksp =...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online