# q11asol - has a K sp value in water of 3.091 × 10 –9 at...

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3.091 Fall Term 2004 Homework Quiz #11A solution outline (a) The value of K a for hydroiodic acid HI( aq ) is 3 × 10 9 . Calculate the p H and the p OH of 0.056 M HI( aq ) in water. HI is a strong acid complete dissociation 0.056 M HI(aq) 0.056 M = [H + ] = [I ] pH = –log 10 [H + ] = –log 10 0.056 = 1.25 pOH + pH = 14 pOH = 12.75 (b) The fictitious compound, pandemonium carbonate (Pn 2 CO 3
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Unformatted text preview: ), has a K sp value in water of 3.091 × 10 –9 at room temperature. Calculate the solubility of Pn 2 CO 3 in water. Express your answer in units of molarity. Pn 2 CO 3 = 2 Pn + + CO 3 2– ∴ K sp = [Pn + ] 2 [CO 3 2– ], but [Pn + ] = 2 [CO 3 2– ] = 2 c S ∴ K sp = (2 c S ) 2 c S = 4 c S 3 ∴ c S = ⎜ ⎛ K sp ⎟ ⎞ 1/ 3 = 9.18 × 10 − 4 M ⎝ 4 ⎠...
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## This note was uploaded on 11/02/2009 for the course CHEMISTRY 3.091 taught by Professor Donsadoway during the Fall '04 term at MIT.

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