q11bsol - 3 has a K sp value in water of 3.091 × 10 –9...

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3.091 Fall Term 2004 Homework Quiz #11B solution outline (a) The value of K a for hydrochloric acid HCl( aq ) is 1 × 10 6 . Calculate the p H and the p OH of 0.065 M HCl( aq ). HCl is a strong acid complete dissociation 0.065 M HCl(aq) 0.065 M = [H + ] = [Cl ] pH = –log 10 [H + ] = –log 10 0.065 = 1.19 pOH + pH = 14 pOH = 12.81 (b) The fictitious compound, administratium fluoride (AdF
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Unformatted text preview: 3 ), has a K sp value in water of 3.091 × 10 –9 at room temperature. Calculate the solubility of AdF 3 in water. Express your answer in units of molarity. AdF 3 = Ad 3+ + 3 F – 3 ∴ K sp = [Ad 3+ ][F – ] , but [F – ] = 3 [Ad + ] = 3 c S ∴ K sp = c S (3 c S ) 3 = 27 c S 4 ∴ c S = ⎜ ⎛ K sp ⎟ ⎞ 1/ 4 = 3.27 × 10 − 3 M ⎝ 27 ⎠...
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This note was uploaded on 11/02/2009 for the course CHEMISTRY 3.091 taught by Professor Donsadoway during the Fall '04 term at MIT.

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