# 34 - MasteringPhysics Assignment Print View...

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Unformatted text preview: MasteringPhysics: Assignment Print View http://session.masteringphysics.com/myct/assignmentPrint?assig... 1 of 15 17/4/07 15:51 [ Assignment View ] E lisfra i 2, vor 2007 34. Geometric Optics And OpticAl Instruments ssignment is due At 2:00Am on WednesdAy, JAnuAry 17, 2007 Credit for problems submitted lAte will decreAse to 0% After the deAdline hAs pAssed. The wrong Answer penAlty is 2% per pArt. Multiple choice questions Are penAlized As described in the online help. The unopened hint bonus is 2% per pArt. You Are Allowed 4 Attempts per Answer. Basics of spherical mirrors followed by increasing complex problems Understanding Spherical Mirrors Learning Goal: To be able to calculate locations and heights of images formed by spherical mirrors, as well as to understand the qualities of such an image. In this problem, you will learn to use the spherical mirror equation: . This equation relates three quantities important to the formation of images with a spherical mirror: The object distance is the distance from the mirror to the object, along the axis of the mirror. The image distance is the distance from the mirror to the image, along the axis of the mirror. The focal length is an intrinsic property of the mirror. It is equal to half the radius of curvature (i.e., ). The equation given above allows you to calculate the locations of images and objects. Frequently, you will also be interested in the size of an image or object. The ratio of the size of an image to the size of the object is called the magnification; it is given by , where is the height of the image, and is the height of the object. The second equality allows you to find the size of the image (or object) with the information provided by the spherical mirror equation. All of the quantities in the above equations can take both positive and negative values. Positive distances correspond to real images or objects, while negative distances correspond to virtual images or objects. Positive heights correspond to upright images or objects, while negative heights correspond to inverted images or objects. The following table summarizes this information: Real Virtual Real Virtual Upright Inverted Upright Inverted Focal length can also take positive and negative values. Positive corresponds to a concave mirror, while negative corresponds to a convex mirror. While it is possible for or to be negative, this can happen only in situations with multiple mirrors or mirrors and lenses. In this problem, you will consider only a single mirror, so and will be positive. You will begin with a relatively standard calculation. Consider a concave spherical mirror with a radius of curvature equal to 60.0 centimeters. An object 6.00 centimeters tall is placed along the axis of the mirror, 45.0 centimeters from the mirror. You are to find the location and height of the image....
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