{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

HW01solutions - 23.4 Model Light rays travel in straight...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon
23.4. Model: Light rays travel in straight lines. Also, the red and green light bulbs are point sources. Visualize: Solve: The width of the aperture is w = 1 m . From the geometry of the figure for red light, 2 1 m 3 m 1 m w x = + ( ) 2 2 1.0 m 2.0 m x w ′ = = = The red light illuminates the wall from x = 0.50 m to x = 4.50 m. For the green light, 1 4 1 m 3 m 1 m w x = + 1 1.0 m x = 2 3 4 1 m 3 m 1 m w x = + 2 3.0 m x = Because the back wall exists only for 2.75 m to the left of the green light source, the green light has a range from x = 0 m to 3.75 m. x =
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
23.6. Model: Use the ray model of light. Visualize: According to the law of reflection, r i . θ θ = Solve: From the geometry of the diagram, i 90 θ φ + = ° ( ) r 60 90 θ φ + °− = ° Using the law of reflection, we get ( ) 90 90 60 φ φ °− = °− °− 30 φ = ° Assess: The above result leads to a general result for plane mirrors: If a plane mirror rotates by an angle φ relative to the horizontal, the reflected ray makes an angle of 2 φ with the horizontal.
Background image of page 2
23.14. Model: Use the ray model of light. The sun is a point source of light. Visualize: A ray that arrives at the diver 50 ° above horizontal refracted into the water at θ water = 40 ° .
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}