Phy102&amp;07-S-ms2

# Phy102&amp;07-S-ms2 - Physics 102 Midterm(2 Solutions...

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Summer 2206/2007 Part I: Solve the following Problems 1. A copper wire of length L = 100 m connects two points A & B. The electric potential at point B is 25 V less than that at point A. If the resistivity of copper is 1.7 × 10 -8 Ωm find the magnitude & direction of the current density in the wire. 1 Vm 0.25 100 25 L ΔV E = = = 2 7 8 Am 10 1.48 10 1.7 0.25 ρ E J × = × = = from A to B. 2. A light bulb of 18 W power has a potential difference of 9 V across it. How much charge goes through the bulb in 4 hours? 2A 9 18 i Vi P = = = C 10 28.8 3600 4 2 t i q 3 × = × × = = 3. In the circuit shown find the power dissipated in the 24 Ω resistor. Ω = = + = 8 R 24 3 24 1 12 1 R 1 1 1 Ω = + = 24 16 R R 1 2 current through R 2 resistor A 3 4 24 32 i 2 = = P.D across V 3 32 R 3 4 V R 1 R 1 1 = = = V 3 32 V resistor 24 across P.D 1 R = = W 4.74 3 32 24 1 24 V P 2 2 R 1 = = = 4. In the figure each capacitance C 1 is 13.8 µF & the capacitance C 2 is 9.2 µF. Calculate the equivalent capacitance of the network between points a & b. For the 3 capacitors on the right μF 4.6 C 3 1 C 1 eq = = parallel in are C C eq 2 '' ' eq 2 eq C C C 13.8μF = + = Finally C 1, eq C , C 1 are in series & as they are all equal μF 4.6 C 3 1 C 1 eq = = A B L = 100m 2 Marks 2 Marks 3 Marks 3 Marks a b C 1 C 1 C

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## This note was uploaded on 11/03/2009 for the course PHY 101 taught by Professor Exams during the Spring '07 term at Kuwait University.

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Phy102&amp;07-S-ms2 - Physics 102 Midterm(2 Solutions...

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