Lecture 14 - = core R R di di di dt di N N i N i dt d N P P...

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CF Procedure to Solve a Problem with Ideal Transformer (1) UCF ± Impedance transformation from back to front ± Circuit analysis at the front ± Work from front to back
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CF Procedure to Solve a Problem with Ideal Transformer (2) UCF
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CF Example (1) UCF Solution in trans1.m
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CF Example (2) UCF
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CF Example (2) UCF
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CF Non-Ideal Transformer (1) UCF μ ) 1 ( r s s p p core i N i N = R φ core s s p p i N i N R = = = core s s p p p p p i N i N dt d N dt d N v R = s p s p core p i N N i dt d N R 2
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CF Non-Ideal Transformer (2) UCF = s p N d N 2 s p p core p i N i dt v R 2 core p M N L = R Define: Magnetizing inductance, very large s p s p M i N N i i = Magnetizing current dt di L v M M p =
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CF Non-Ideal Transformer (3) UCF (2) Leakage Inductance: Primary: dt d N v P P P φ = i N i N lP M P + = P N 2 core R S S P P M = lP lP L R =
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CF Non-Ideal Transformer (4) UCF dt d N dt d N v lP p M P P + = φ i N dt d N i N i N dt d N lP P P p S S P P P +
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Unformatted text preview: = core R R di di di dt di N N i N i dt d N P P M P lP P P S S P P + = ' 2 core 2 R R dt L v dt L dt L lP P lP M + = + = Secondary: lS M S + = lS S S lS i N R = t di L v t d N t d N d N v S lS S lS S M S S S S = + = = ' lS S lS N L R 2 = dt dt dt dt CF Non-Ideal Transformer (5) UCF p i i t di L S lS t di L P lP s p s i N N ' ' s dt dt P v S v P v S v M i s inductance leakage small are and lS lP L L dt d N v M P P = ' s N dt d N v M S S = ' di S ' s p p M i N i i = dt L v v lS S S =...
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Lecture 14 - = core R R di di di dt di N N i N i dt d N P P...

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