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homework 11 - PH 132 SPRING 2005 HOMEWORK 1 1 Assigned CIA...

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Unformatted text preview: PH 132 SPRING 2005 HOMEWORK # 1 1 Assigned: 03/28/05 CIA. ‘30.” .§)%)22323;Z¥j 30931,:33 2% cm: : WE ,7 gig In Fig. 31-35 a IZO-rum coil of radius 1.8 cm and resistance 5.3 Q is placed outside a solenoid like that of Sample Problem 31—1. If the current in the sole- noid is changed as in that sample problem. what cum-em appears in the coil while the solenoid current is being changed? 53m 4 we? 1.4% _.____ A1- : o —— 3‘3Xl5 a5xlo"3 )(::s>[email protected] @W U 4) --2. ~52. ——.o-132xro 353} :~. floqamo V ##A W . In Fig. 31—42, a wire forms a closed Circular Ioop, with radius R = 2.0 m and resistance 4.0 0. The circle is centemd on a long straigh: wire; at time I = 0. the current in the iong straight win: is 5.0 A rightward. Thereafter, the cument changes according to f = 5.0 A - {2.0 Aislkz. (The straight wire is insufated, so there is no eiectricat contact between it and the wire of the Imp.) What an: the magnitude and direction of the current induced in the loop at times I > 0'? Fig. 51-42 Problem 20. A4 file 6m 44m) «I‘M fialafi '1 s ‘udv 712a PW me=o——» - No+2: WM dam md m ”numbers gm»: I‘m TEE mem v‘véolve w. “0T5? om ~H~L 54%;?” mm. Cmvws aw Cwmt‘ . For the situation shown in Fig. 31-44, a = 12.0 cm and b = 16.0 cm. The current in the long straight wire is given by i = 4.50:2 — 1013!. where f is in am- peres and r is in seconds. (3) Find the emf in the square 100p at r = 3.00 s. (b) What is the direction of the induced curregit in the leap? W a. UV A'E {:55 2 g, Folio-WW? 51W (3.? Lewis iqw‘. Fin. 3144 Problem 22. Take. Liza ai- 1119. PoSi‘Ha/taii- m Mfi‘ EWW Lair-e. * - ‘ 5 aha-Ham M744 Frat;— I LMQ'ngc [Cp- 7/5“ 0-}4-64- bag/1) £15 @Wiockwisg. ( . In Fig. 31443, the square 5 loop of wire has sides of length 2.0 cm. A magnetic field is di— recled our of {he page; its mag- nitude is given by B = 4.09% where B is in tesias. r is in sec- onds, and y is in meters. Deter— mine the emf around the square at: = 2.5 s and give its direc— tion. 55m {M 0H Canada, 519%? caf— w 1'41“» dt/ (Lt Ca'WMaJ—Q Lf - A camel—{mg 4'0 1—2-9! X Fig. 51-45 Problem 21. ATEOL (9.12 SWLP = om (544N110 —‘ @dfi) 0:5}; B [£0199 M’- 34.47 : I: (4+.le £4,312; L [email protected](fio 2 [LEE—5: 2+1? (at: Ldifikgflw) 2933 A; + ”295, 2m 15 QLOCKMJSE "w- J . If 50.0 cm of copper wine (diameter = 1.00 mm) is formed into a circular ioop and placed perpendicuiar to a uniform magnetic field that is increasing at the constant rate of 10.0 mTfs, at what rate is thermal energy generated in the ioop‘? 55m 11w > (7055 $244M L— Area. .919. wiya ._ t 1. " AwlYfi = TTY-wiye “Minn-WW l ' In Fig. 314?}. a long rectangular conducting loop, ofwidth ' ' L, resistance R. and mass m, is hung in a horizontal, uniform 50 SHEETS 22—142 IOO SHEETS 22-144 200 SHEETS 22-14! 49 o AMP leeflrL, 3m magnetic field B that is directed into the page and that exists only above line act. The loop is then dropped; during is fall, it aeoeler— E»: -— E?) C ates until it reaches a certain terminal speed v,. Ignoring air drag, . - find that tenninai speed. x . F,» n 7/1; -Farad43's Law) Q1123 LawJ Ohm‘s Law, ”49th Fort: and Wire} AM: 2"‘74w _- 83 droppah #7: {pop rhmujh a majpafi'c {Fe/a: we WJW rhdwe a carrmf m 1% 100p. 01’ on? wfl/ +64: Imp expenam‘e 62 16mg diet 7%; firm/#5 , bm‘ ' 62/50 a magnet: firce i €15 1'3“? Ad :flfi ngjg'dfia'e BA A 3‘5 fi'me depenéénf: We)? L369 dfi 7”? 2% de ' ggh 74" o __ g . l ‘ E Ti— Lang‘s Laud" 353 is decreaslhj 04 F5 steamer}, )To oppose 7426 five Ma’uad cammz‘ mot mt d mgr-am "(é/x2725 Me page. szhj #221 right flan/ml!) (‘ mw+ be. c/océwttse. New w“z Can 1%(1 7416 magma 15%: on 7% {cap ~‘ f1: look m‘ and tilde? —» . £1.52 FWD???" gr: 59613513 Br— 12.)] 3 "‘ tag? REmetr P13,- m +416 dfrrofi'o‘n .4. m‘ +h: cur/m“. .— ~ ,~ A A ‘ A 653‘ t[fiftléJ)XB(~a):/‘ tgat ere =0 'The LUEI'SN +3116 = “mgj '55:? "*' fir: ‘F:+ E: '3 L'LBJ’ “ mflf ~'—‘ m'f’: O (EM 47‘ (msfiim‘ 14:) [LB rmg a f: £521 : SUV“ E L5 R 22 142 100 SHEETS 22-144 200 SHEETS M 3)sz ANS. 2244] 9 ________.o_.___L__.__ __ fl .__ fl Two straight conducting rails form a right angle where 6 1 ‘ “—59-“ ,u 4. their ends are joined. A conducting bar in contact with the rails l V6” - /U' - 6. 20 Ed starts at the vertex at time t = 0 and moves with a constant veloc~ "J", 5 T "‘ ity of 5.20 mfs along them, as shown in Fig. 3166. A 0.350 T 5 ‘ 0' % magnetic field points out of the page. Calculate (a) the flux through the triangle formed by the rails and bar at t = 3.00 s and (b) the emf around the triangle at that time. (c) If we write the emf as 55 = or“, where a and n are constants, what is the value of n? 5 O SHE ETS 22 I42 ‘IOO SHEETS 22-144 200 SHEETS 22-14] Manefi'c Wax ,0 Etta/aged 6% at) @BrjE»d?=jed/4 = BA We need Fl= fire: of thewhole. +flhfljzg: (45mm) alfrdc dig” :- s 31 (e dc ms {50¢er trio ”3 ks D @ A = my: my: (1'4“ is mOWlta WWI a Cmdanf tag/cg?) 95¢) = Bf} : szfi 43(3553' {0. 350 rpm 0 “@7391 2 8512 7PM? 1 Amt lb) 2: ”123;. wow): flew: 157% l ' i 23 (as): £10350 TJK5—ZOMEYGS): -A/Us. . I W—hfi :: ’ngzt3Q/t:dfi 5O flzllms. a) 5 I 1‘ Comm. I 50 SHEETS 114 4] 22442 100 SHEETS T1444 200 SHEETS «r9 Figurfi 3149 shows a rod of length L caused to move at constant speed v along horizontal conducting rails. In this case the ' magnetic field in which the rod moves is not uniform but is pro~ ' vided by a cunent z‘ in a long wire parallel to the rails. Assume that v z 5.00'mis, :1 =10.0 mm, 1. =10.0 cm, and r = 100 A. (a) Calculate the emf induced in the rod. (b) What is the current in the conducting loop? Assume that the resistance of the rod is 0.400 (I and that the resism’nce of the rails and the strip that energy being generated in the rod? (d) What force must be ap- plied to the rod by an external agent to maintain its motion? (e) At what rate does this external agent do work on the rod? Compare this answer to that for (c). X x X x x X x X X X X x x X x ): -' x ‘ . :v: x x >1 x x x x x x x x x I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I I fl. 5593139an 2231:” 2ft 3 : Z4‘K/0'4l/ ANS. cannects them at the right is negligible. (c) At what rate is thermal ' @szg‘dflr : de/El .' 3 196m +ie tern: (3 not 01/4 2‘ X6231 pull 14 ml o-F lite integral. dfl : a l: X 1% o ’ ’ I ”E 9”” : é—g’fifitmt} *Jn dJ:Mfl-K%¢> ? e tit * elem/w Me) %= wee/e? i... "El; (Exit/em.- rte: 5.00 mg l fl": /0-0mH-‘ {amt/o" 5m L:/§.0m: 0.300,,1 I c. : /00H EM -‘ a) 2. MI 6) Eh ,(fiermelemqj dt'fl‘pmledj Cl) Fe (cedar/mt 6mg) ”Fame (ml: at workdm 53 5) Compare eh (Md 1% “’767‘31’14‘2-50-we annat just 0f 2?? .b) I: 3%: -AA13. @8(w1'~lei'l 3 GM ot'liw. Page) :3 {lid/605,50 I shouts! Create a meg/Lafiz film/(>292: flu page. Z" musaL be C/OckwiLse. 0) Pm: I01? Mid/04w ANS. _ ' ; 22 U” 50 SHEETS 22-142 100 SHEETS 2‘2 144 200 SH£ET5 15mm ?chanfies m but more. ama- WM: weird) vtfiguc ab fansrdpra smafi’ sejnum‘ 091% rad, d3) 1% find a; 5‘ 0!? Td*x?:f(d3fXBC—£)> =rach—f‘) 8% (B for a wfre) O'fF—g ”I 650/qu .2779 mL A “-’>_ -2“ ed A -—_T“ ()4 dyflwlfl L _ é'j 2773096 * %‘fl‘g ZLWWMh .k _ 1 . A I UP. A long solenoid with a radius of 25 mm has 100 tumsfcm. A single loop of wire of radius 5.0 cm is pieced around the sole— noid. the central axes of the loop and the solenoid coinciding. 1n ' 10 ms the current in the solenoid is reduced from H) A 100.50 A alauniform rate. What emi’ appears in the loop? At .- {:sz : [01715 :, OIS W 5 0m: 5mm and r 2 25m : 2.6x/o'2m 22-142 IOOSHEETS 22 NM 200 SHEE'I’S 12—1131 Faradayb Law 04 fndacfibn 1.; -—-=- r—‘b fig 2 : '— 33 @133: jB'dn In a fioknofd) E runs chum—1"? dt = . axis) In #26 same @3qu as A. 580% 6050 - - :iBo/H = Bjdfi = BA a. Z = "EKBHD : -/3\ of [-35 "Ad 991%) B far a Salmons/Qua (if dfi (ii-E d6 . flog Sees) I onig i; dependsan fi'mc. ..__ ‘ ““pi/(jm 63’; since Hie summit is dicrmihj In a um’farm yak, i “'6 we. ran wisp/ace 9:: WW: A_L:_ ' dc— A15 ,: "#i/um é; : “—Fyzon (i231) I _ _ At at A? Mat were ”mi/F651 {£ch emails 2 =5ro»».séwimal Wat-7 offiwmoi‘d 2 “(TH— lab“ (62’ Li) (3:0 Ouffiri‘lfl CkJJ/Efldiifif) At 2 — rr(2.5xxo’ m)10.ZOF/0-b%m)(fi>(m) A) #045 - . ....._..... 91,4le fix “‘5“ 0‘9 Ta; .16 tardy. :. BA '- _ BOWL) —-(_'D ...
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