# homework 8 - PH 132 SPRING 2005 HOMEWORK # 8 Assigned:...

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Unformatted text preview: PH 132 SPRING 2005 HOMEWORK # 8 Assigned: 02/28/05 3210,Zq)7—’S‘) Lot/b Zq—SHP 5 2 «— 1' m 526;}; C? 50 S HEETS 22-142 [00 SHEETS 22-144 200 SHEETS 22-141 CH An W65 electron that has velocity V = (20 x 106 mlsﬁ + (3.0 x 10*6 misn’ through the magnetic ﬁeld E = (0.030 T)? — (0.15 “mi. ' (a) Find the force on the electm 03) Repeat your calculation for a proton having the same velocity. ' ‘ A MMﬂC Fact: 35 0 ouA 83-65- .‘Ef'd. MOVING “2-006 ' WEM 73“): 54125241. 3" = Dyna—’9‘: +(3. canoe-'35.? 5.7-(00307'51-(0491‘53 ." 623. V = 2007.1“) 5 X 65. .5 By = ,_.D, e = hex/o”? l\x l n \ _ r £7 ' An electron is accelerated from rest by a potential difference of 350 V. It then enters a uniform magnetic ﬁeld of magnitude 200 1111" with its velocity perpendicular to the ﬁeld. Calculate (5' (a) the-speed of the electron and (b) the radius of its path in the '. magéifijiieé'a We . V: 380 V Elm UNEgg-mb 7794-.- ScENARIO : B: 0.2.00 7" “Mane-3455113 ﬂ/L'Hﬁf m?ﬁ_... ’j_ v; =- c: 3‘3 game» WERE? Mug: BE A” 51-15-112“: _H JELB THE‘ “Fm-5:7" Jae émkh . N91— ; Emcee" 7?»; rs M £55. #— £¢ELTRO~5 .r'r Lulu. 333 MOVE: J» A 1:12. OWOSJTE "“ To 'THE' b)K.0F 3 "HQ a._- ___b \$2.2. 90 \f Am: 5 A25 232 Amrg—PAmMEL H5725. IN 77-}! gee—walk TIP-ﬁlo“ THL’RE W- _. N97153: HEM: VAN: B A7243 Emmbbubl'rk. . 951M Newman’s aWQ LAND : m In 2561b» - W6;— 'w:§‘ More .. e " = 1M 'x w v *\$ F=-e_\7‘x§ a . _ ah =-‘QVEML10 I“ = -e.\!'B I @ l _ " In Fig. 29—34, acharged par- ticle moves into a region of uni— form magnetic ﬁeld 3". goes through half a circle, and then ex- its that region. The particle is ei- lhera proton or an electron (you must decide which). It spends 59' 29'“ Pmmcm 28‘ I30 115 within the region. (a) What is the magnitude of E? (b) If the particle is sent back through the magnetic ﬁeld (aiong the same initial path) but with 2.00 times its previous kinetic energy, how much time does it spend wimin the ﬁeld? 50 SHEETS 22 I42 100 SHEETS 22-144 200 SHEETS 22-14! e i PaSITIVE H525 ’ ‘T‘o F'R—DVIM 73% I Fem basameb IMTHE FlG-uZE. I i l OEIG'IM‘KH)? 1 2 K : JiMV “0‘0" 1 IT- M) . EEM‘ ’ ._._._. t go _ KI: SO SHEETS 22-142 IOO SHEETS 22 144 200 SHEETS 22-14! e s I l I l l i i In a certain cyclotron a proton moves in a circle of radius 0.50 In. The magnitude of the magnetic ﬁeld is 1.2 T. (a) What is the oscillator frequency? {b} What is the kinetic energy of the pro— ton, in electron-volts? _ OQMLLATon .FREGP, 50 SHEETS 22-142 100 SHEETS 22-144 200 SHEETS 22-141 6 allan ' the plane of the Wire coil contains . the least current E through the coil ' .I will prevent the cylinder from rolling down a plane inclined angle 6 to the horizontal. in the presence of a venical, uniform 45' t - Figure 29-38 shows a wood cylinder of mass m = 0.250 kg and length L = 0.100 m. with j N = 10.0'tums of wire wrapped I around it longitudinally; so that the axis of the cylinder, What is '“Ii‘ ﬁgmeﬂc ﬁeld of magnitude 0.500-T, if the plane of the coil is girdle] to the inclined plane? ssm 22-h" 50 SHEETS . 22-142 100 SHEETS 11' 144 200 SHEETS 6 _ ma 1 n 1 1 2b) _- _{_ cui-rem 1001?, canying a current of 5.0 A, is in the shape of '__ mangle _w1di sides 30, 40, and 50 cm. The loop is in a - I magnetic ﬁeld of magnitude 80 mT whose direction is ﬂ 1‘ 30W :70. 30M b: 40cm ’0. Yam C 2 EOmé 0.50M 60/» b) T bA/X Epohbou’fdf-fﬁepaje ; J som'ﬁb” 04431131553 dpale NOW and brfﬂe @589 m? AH (mg / x009) .We £275 d9!“ #16 majmﬁcde air/J": ﬂax? —¢(é)ab ' Ndeﬂ Ls aim/r3391 5W5“: 79“”? W Mm" ’Ails‘ of 71w camsm‘ a?er ma! mi 511m, beam [’7‘ )3 ma‘ needed 75 ﬁnd ﬁe Mfmw. We hm wamJMw/ «'7‘ As (mnkrc/ocwirejna’ Manna doom/IMF IerVuu’ (Is (In 4 .4 {hr same adrecﬁan a; A"? 2T1: ai‘ﬁer m 426:. ~42. dr- 6. 44%61534. 60m? 4 {Ii/11‘ kin/wk, Wm av 13th :11 We mm if m 51am, oar Mam am A» Medan OfﬂﬁdNJ/a“ -’ k. lﬂwf/Masme 7:1 5" 50 ea: 620° Twig -‘ (0.30.4mZX802r/637) — ANS. Male: 75 1%! #2? aim:sz of 7"“: we. 1%: my: hand m4: : /,\ kxf=J --=» T7x§=ﬂ£xﬁt 75w?) 7‘“: #3? S 2/ 1 - 29-415 etmm a WP ' I C - _ ABCDEFA carrying a ‘ . ‘ r « u ~§=S,00A.Thesid650f " L . " m wane-1w them" ._ __ . _ FIB : 20. 0m: 0. 200m "axes, withAB = 20.0 cm, BC = 30.0 cm. and FA =ﬂ \ .J cm. Calculate the magnitude and direction of the magnetin 3 OW : M dipole moment of this loop. (Him: Imagine equal and opposite‘ currents t' in the line segment AD; then treat the two rectangular : O M ; OJOOM loops ABCDA and ADEFA.) FM.-/'i”1%r ABCDEFA‘ ! 3§§ i §§§ . . 'aneﬁ'c, btpok: Momen'f “‘3’ .2 ‘3? ""'a lamp}; s/uquCD {II/Mﬂbéf //.-’ Nil? = (3H (NH) amazed—mu (mXaof use #m n" Hima’mé 1b 3e7‘ 74m 6&7?ch _ r FéC/I ‘* 2 (5.0%) {0.100m)(0. 30m)“ # (Room/9.200de3001303, ﬁmm J ' F“ _ . t - ‘ 0.26024»: J h 0.300ﬂng?12/ ANS, . VF 024(/.50AM2—)2+ (0.500Am2)?' 2%. _ _ -0300 A a 6:739?! (1:50)“ (51% 7'33 lo/ﬂﬁe. A415. (K. ./ - —_ F __., a . A length L of Wire carries a current 1'. Show that if [he ,__. . formed into a circular coil, then the maximum torque in i | magnetic ﬁeld is developed when the coil has one turn onl p I that maximum torqne has ﬁll: magnitude 7 = LZL‘BMa-r. l I ,I F N alt—c9555 QRwLA/"L Loo? RE WMEB («J/TH A MIKE 0F LE/xheTH L E Tﬁgm EACH Loo? HA5 A OKLUMFERE1QCE ,2: ' 0"" _£—_. '9 ' ' 3 :‘4: "— N ' 20-- ﬁ— «2W2 I as: I g 2: ___IL__-—-—- I ®® l. F a 4YC2TFN L?— — HWN‘ Max:577; DIPOLE MOMENT VEJDTLAI\$t , FDR-735501 !E = N . AS I mme GARZV/ADG. A cur.ng ? TM? I i 50 SHEETS 22-142 ")0 SHSETS 22 144 200 SHEETS 22-14] ’0) _mm stationary circular wall clock has a face with a radius of Six turns of wire are wound around its perimeter; the wire a current of 2.0 A in the clockwise direction. The clock is Where there is a constant, uniform external magnetic ﬁeld itude 70 mT {but the clock still keeps perfect time). At 1:00 pm, the hour hand of the clock points in the direction _'_ternal magnetic ﬁeld. (a) After how many minutea will the I: (1 point in the direction of the torque on the winding due '2netic ﬁeld? (b) Find the torque magnitude. _. N= (b , 5:20;) dbcéwt‘se. B: 70m7= 70 x/o'BT a/r'fmd w( 1 1529.4-' a.) df/eaﬁan at 7"“ b) mdymyrde. of. F -' pot/IISAIWD, #2 page. (See mm in cam-66) A =' yak , 1? 2 83‘ ' Tryﬁxﬁj =/c8(-£xf) =/M8? _ - T/ze mr‘na/e @27/ MY/ pothrkfﬁe famm 474% mg. “9) ’33:? KgyBsM?0° WE WWHB =A/s‘(nra)B . ‘ 9(2-0A>W(0J5m)‘(7ox/o-37)—m5. . inﬁlx’K : high/en - r: (Sam: 0. (5m 50 SHEETS 22-144 200 SHEETS 22-!“ n 22-142 100 SHEETS ® I ductor that lies behveen x = 1.0 m and x = 3.0 m. Consr‘clera smal/ segmenf dz .- df = NEW" d§=fdxfx T? Mow t'r'I-ltjmk 40 {Had Me ' 32 Xi x-l 3 SIP. A long, rigid conductor, lying along the x axis, carries a current of 5.0 A in the negative direction. A mgnetic ﬁeld B is present. given by B = 3.0i + Bﬂﬂj, with x in meters and B in milliteslas. Calculate the force on the 2.0 m segment of the con- : -I (MMQOM) ~ (;,0M)3]!: =' ﬁrm. on a curren+ Carrgt'hj win a? 1'5 (In #76 same darmmn as #:e (Barred: d? 2 * dart? 'foﬁ/ 76m: barium? 7:, dm/ 3’: i: x A ._. ?=j-z"dxgx'§’= .L dX(-Z“)X_(3.03+X.0x=f) "' 0.35/‘0154 Klaus. ——-——~—.-—...——.__u__. . mﬁmm um... e. .. mm. .mm maw- “Maﬁa- mm" 1 .-———-.———u—-.——__.___ PH 132 Suggested Problems ...
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## This note was uploaded on 11/04/2009 for the course PHYSICS PH13100 taught by Professor Dr.wick during the Spring '09 term at Clarkson University .

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homework 8 - PH 132 SPRING 2005 HOMEWORK # 8 Assigned:...

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