Unformatted text preview: pattern. Because .25 x 2 = .50, the second binary digit to the right of the point is a . So far, we have .625 = .10?? . . . (base 2) . Step 3 : Disregarding the whole number part of the previous result (this result was .50 so there actually is no whole number part to disregard in this case), we multiply by 2 once again. The whole number part of the result is now the next binary digit to the right of the point. Because .50 x 2 = 1 .00, the third binary digit to the right of the point is a 1 . So now we have .625 = .101?? . . . (base 2) . Step 4 : In fact, we do not need a Step 4. We are finished in Step 3, because we had 0 as the fractional part of our result there. Hence the representation of .625 = .101 (base 2) ....
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 Fall '08
 STANKOVIC
 Computer Architecture, Binary numeral system, binary digit

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