This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: HW#5 SolutionGuide Using Matlab REMARK: We will discuss this in class, specially problem 6 for the Eigenvalues/vectors of B. As the eigenvalues of B are Lambda1=(15+(297)^0.5)/2, Lambda2==(15 (297)^0.5)/2, and Lambda3=0. It you use approximation of the first 2 eigenvalues, you would get numerical errors and NO (nonzero) eigenvector can be obtained. This simple matrix shows that careful use of any computational software (including MATLAB) has to be applied as a supportive tool, not an end of/to itself. For the purpose of grading, we shall not penalize you. However, this is a challenging problem that illustrates the need to be careful in applying these software tools. ____ Given X1=[1 2 3]' X1 = 1 2 3 X2=[4 5 6]' X2 = 4 5 6 X3=[7 8 9]' X3 = 7 8 9 B=[X1 X2 X3] B = 1 4 7 2 5 8 3 6 9 rank(B) ans = 2 poly(B) ans = 1.0000 15.0000 18.0000 0.0000 %This computes the coefficients of the characteristic polynomial of the matrix B as in %det(Lambda*IB)=0. A=[1 3;2 4] A = 1 3 2 4 rank(A) ans = 2 1) %Rank of a matrix Use Rowreduced Row Echelon Form REF A A = 1 3 2 4 %Apply the reduction to the Identity matrix and premultiply it to A at every step....
View
Full
Document
This note was uploaded on 11/04/2009 for the course ECE 280 taught by Professor Mukkamala/udpa during the Spring '08 term at Michigan State University.
 Spring '08
 mukkamala/udpa
 Electrical Engineering

Click to edit the document details