Lecture+Ch+10+A

Lecture+Ch+10+A - Welcome to Chem 1C Prof Pat Farmer TAs...

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Unformatted text preview: Welcome to Chem 1C Prof. Pat Farmer- TAs, Amanda and Shane- online only during this week- Tutoring available- Facebook Class page - Textbook homework- Electronic Homework- Exam schedule- First Midterm April 21 !!! Electronic Homework c02 Molarity - Unit Quiz 02 5 Apr 2009 at 11:00 PM c02 Solution Stoichiometry - Unit Quiz 02 5 Apr 2009 at 11:00 PM c10 Chemical Equilibrium - Equilibrium Constant 10 Mastery 5 Apr 2009 at 11:00 PM c10 Chemical Equilibrium - Equilibrium Concentrations 10 Mastery 12 Apr 2009 at 11:00 PM c10 Chemical Equilibrium - Stoichiometric Relationships 10 Mastery 12 Apr 2009 at 11:00 PM c10 Solubility Products - Solubility 10 Mastery 12 Apr 2009 at 11:00 PM c10 Solubility Products - Common Ion Effect 10 Mastery 19 Apr 2009 at 11:00 PM Ch 10 – Equilibrium In 1B, you discussed chemical reactions that go to completion:- limiting reagent- % yield- stoichiometry However, many reactions do not go to completion, and have a much different way of signaling their end. To illustrate the difference, let’s play a bball game (really a simulation). Assume that we are throwing at the same rate- and the game, or simulation, ends when the amount in my bucket doesn’t change! Practice problem #1 : the “run out of balls” game If I have 15 balls in my bucket and Superman has 20 balls in his bucket, how many balls will be in the bucket on the other side of the fence at the end of the game? PJF = L.R. I throw 15 + 15 from Superman = 30 in the bucket Let’s make a plot of the # of balls in each bucket as a function of time for this simulation: time (arb. units) # of balls 15 20 30 “other side” Superman PJF Ch 10 – Equilibrium 1 PJF + 1 SPM Æ 2 Balls right of net This same “model” can be applied to a chemical reaction. PCl 3 (g) + Cl 2 (g) PCl 5 (g) Initial conditions:- 1¡mol¡PCl 3- 2 mols Cl 2- 1 L reaction vessel A plot of this complete reaction would look like so: time (arb. units) molarity 1 2 Cl 2 PCl 3 PCl 5 Final conditions:- 0¡mol¡PCl 3 remain- 1 mol Cl 2 left over- 1¡mol¡PCl 5 created (PJF) (Superman) (“balls right of net”) Ch 10 – Equilibrium Ok, now let’s revisit the simulation: If we assume each of us can throw at a rate which depends on the # of balls in our respective buckets, at some point the simulation ends when the number of balls in each bucket no longer changes! The important difference here is that even though the simulation ends, the throwing still continues !!! Ch 10 – Equilibrium We’ll call in Mikey! 1 PJF + 1 SPM Æ 2 Balls rt of net 1 MKY Æ 1 Ball lft of net Let’s plot the number of balls in each bucket again: time, arb. units # of balls 15 20 Superman Me “End” of the simulation comes when:- “rate of throwing” back and forth is the same- number of balls in each bucket stops changing “end of game” , Mikey Ch 10 – Equilibrium Let’s extend this simulation to the gas phase reaction we examined earlier, and allow for the BACK REACTION of PCl 5 : PCl 3 (g) + Cl 2 (g) PCl 5 (g)...
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This note was uploaded on 11/04/2009 for the course CHEM Chem 1C taught by Professor Farmer during the Spring '09 term at UCL.

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Lecture+Ch+10+A - Welcome to Chem 1C Prof Pat Farmer TAs...

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