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term%20test%201%20plus%20answer%20key - Name: _ Date: _ 1....

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Name: __________________________ Date: _____________ 1. In hogs, a dominant allele B results in a white belt around the body. At a separate unlinked locus the dominant allele S causes fusion of the two parts of the normally cloven hoof resulting in a condition known as syndactyly. A belted syndactylous sow was crossed to an unbelted cloven-hoofed boar, and in the litter there were: 25% belted syndactylous 25% belted cloven 25% unbelted syndactylous 25% unbelted cloven What are the genotypes of the parents? A) B/B ; S/S x b/b ; s/s B) B/b ; S/s x b/b ; S/S C) B/b ; S/s x B/B ; s/s D) b/b ; S/s x B/b ; s/s E) B/b ; S/s x b/b ; s/s 2. In the cross between A/a ; B/b ; C/ c; D/d ; E/e and a/a ; B/b ; C/C ; d/d ; E/E , what proportion of the progeny will show the dominant phenotype at each locus? (Assume independent assortment of all genes and complete dominance.) A) 1/32 B) 1/16 C) 3/8 D) 9/16 E) 3/16 Page 1
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3. Below is a pedigree of a human genetic disease in which stricken individuals are solid-colored. Apply the laws of probability and calculate the probability the offspring of the cousin marriage 1x 4 will have the disease . A) 1/4 B) 1/3 C) 2/3 D) 1/2 E) 4/9 4. The following pedigree shows the inheritance of attached earlobes (black) and unattached earlobes (white). Both alternative phenotypes are quite common in human populations. If the phenotypes are determined by alleles of one gene, then attached earlobes are inherited as a(n). . A) autosomal dominant B) autsomal recessive C) X-linked dominant D) X-linked recessive E) could be more than one of the above 5. 0 A couple has a female child with Tay Sachs disease, and three unaffected children. Neither parent nor any of the four biological grandparents of the affected child has had the disease. The most likely genetic explanation is that Tay Sachs disease is inherited as a(n) … A) autosomal dominant B) autsomal recessive C) X-linked dominant D) X-linked recessive E) somatic mutation Page 2
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6. The ability of the human body to break down the red color in beets is controlled by an autosomal dominant allele. The inability is recessive, detected by red coloration of the urine (we will call this phenotype 'secretor'). If a nonsecretor woman with a secretor father has children with a nonsecretor man who in a previous relationship had a secretor daughter, what is the probability that their first child will be a secretor girl? A) 1/2
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This note was uploaded on 11/04/2009 for the course BIOLOGY 211 taught by Professor Monica during the Fall '08 term at Windsor.

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term%20test%201%20plus%20answer%20key - Name: _ Date: _ 1....

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