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Unformatted text preview: actual theoretical Figure 2: Error vs. # segments (n) for composite Simpson method 2. Problem 17.10 For MATLAB implementation details, see posted m-±le problem2.m . a) Using the composite trapezoid rule with n=6 gives F=996.14 and d=13.14. b) Using the composite Simpson rule with n=6 gives F = 1042.29 and d = 12.68. 3. Problem 17.11 Using composite trapezoid rule with unequal segments gives F = 526200 N and d = 158.62 m. See problem3and4.m for implementation details. 4. Problem 17.15 The average value for the data given is -0.8333. See posted ±le question3and4.m . 5. Problem 17.17 Using the composite trapezoid rule gives Area = 9.05 m 2 Flow rate = .69625e-01 m 3 /s . See posted problem5.m for details. 3...
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- Fall '08
- #, composite trapezoid rule, 158.62 m