This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Physics 21 Fall, 2009 Solution to HW2 211 Excess electrons are placed on a small lead sphere with a mass of m = 8 . 40 g so that its net charge is Q = 4 . 00 10 9 C. (a) Find the number of excess electrons on the sphere. (b)How many excess electrons are there per lead atom? The atomic number of lead is 82, and its molar mass is 207 g/mol. (a) The number of excess electrons n is the excess charge Q divided by the electronic charge e . n = 4 . 00 10 9 1 . 602 10 19 = 2 . 5 10 10 (b) A mole is 6 . 02 10 23 atoms (Avogadros number). The mass of a mole of lead is 207 g, so the number of lead atoms in 8.40 g is 8 . 40 207 6 . 02 10 23 = 2 . 44 10 22 . The number of excess electrons per atom is 2 . 5 10 10 2 . 44 10 22 10 12 The excess charge per lead atom is very small. 2112 A charge of Q = . 580 C exerts an upward force of F = 0 . 230 N on an unknown charge q a distance d = . 350 m directly below it. (a) What is the unknown charge? (Give the magnitude and sign.) (b) What is the magnitude of the force that the unknown charge q exerts on the charge of . 580 C? (c) What is the direction of the force that the unknown charge q exerts on the charge of...
View Full
Document
 Spring '07
 Hickman
 Charge, Mass

Click to edit the document details