ch2test

ch2test - Fall 2008 tath lU 0 zE*4.\ n^ . !,- 24|5 Name:...

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tath 24|5 Chapter 2 Test (17 Sept.2008) tw Name: SX"l'; lvhro; n^ . !,-- l\intlg, _ lU 04.\ rht I c' zE* Prob. l. Find the general solution of the l't-order oDE 4.! r= tll, / > 0. dttt 5# {*;-q*& p"r* rce) -ra, "ft*= u, tlL ob E cor,. h,t trJu-tE" arr ' ,( S'tl) = S.f-b,") = t (f)= can*t. t^qt"b't t5rtt =Jcrnt Jt+c =' - cost +c grt)=- * + t1 I ,0 ,bh ?*Sry3 Prob. 2. Indicate in the respective spaces the order of the ODE and state whether the equation is li*-".nonlinear. 2 #s *d^ _{-1 dV r_ -, t\t/ '--r I a) :!+4,{y =5f * Or{rr: 1'/ Linear/}lonlinear: Nctrtl,lurql 'dxr b) #.9siny = 6cos2x ora.r' JY tt'v4V|". c) #.9r'sinx = 0 Order: 'J ' Linear/Nonlinear: @ , dv'dlv AV d) *# + 4y = Jy Order: J ' Linear/Nonlinear: l'btLr,^rr' , d'v )r' n r 4V el ---i-+ '^ - 4x Order: \rt LinearA''lonlinear: Nc'uLt !l^ dxz v lg$ Prob. 3. Find the fixed points of the l't-order oDE * = (r -2)(v - 0 . fi"
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This note was uploaded on 11/08/2009 for the course EE 101 at USC.

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ch2test - Fall 2008 tath lU 0 zE*4.\ n^ . !,- 24|5 Name:...

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