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Unformatted text preview: leaving the red 4 multiplier out, while the 11 am class may not have yelled loud enough about the omission to catch my attention!]. x (0.05 x) (6.0) 4 So: x/(64.8 1296x) = 2.5x10 4 x = 0.0162 0.324x 1.324x = 0.0162, so x = 0.0122 Now use x to calculate the equilibrium concentrations in the ICE table above: [Co(H 2 O)6 2+ ] = 0.038 M, [Cl ] = 5.95 M, and [CoCl 4 2 ] = 0.012 M ( l )...
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This note was uploaded on 04/03/2008 for the course CHEM 1A taught by Professor Nitsche during the Fall '08 term at University of California, Berkeley.
- Fall '08