Tutorial Solution - Tutorial Q.1 - solution 1 L1 2 (s + 1)...

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Tutorial Q.1 - solution •F i n d • Solution : () ( ) + + 2 s 1 s 1 2 1 L () ( ) () 2 s c 1 s c 1 s c 2 s 1 s 1 3 2 2 1 2 + + + + + = + + () () ( ) () 1 2 s 1 2 s 1 s 1 1 s ds d c 1 s 2 1 s 2 2 1 = + = + + + = = = () () ( ) 1 2 s 1 s 1 1 s c 1 s 2 2 2 = + + + = = () () ( ) 1 2 s 1 s 1 2 s c 2 s 2 3 = + + + = = () () t 2 t t 1 2 1 1 2 1 e te e 2 s 1 1 s 1 1 s 1 2 s 1 1 s 1 1 s 1 + + = + + + + + = + + + + + L L L L
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Tutorial Q.2 – solution () () () () () t 2 e 2 t 2 e 2 1 s 2 2 2 1 s 1 s 2 1 s 4 2 1 s 1 s 4 1 s 5 s 5 s 2 s 5 s t t 2 2 1 2 2 1 2 2 2 2 1 2 1 2 1 sin cos L L L L L + = + + + + + + = + + + + + + = + + + = + + +
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Tutorial Q.3 - solution
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•R = 1 0 , L=1H, J=10kg-m 2 , T L
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This note was uploaded on 11/09/2009 for the course ENG 91301 taught by Professor Lui during the Spring '08 term at Hong Kong Institute of Vocational Education.

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Tutorial Solution - Tutorial Q.1 - solution 1 L1 2 (s + 1)...

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