lecture7 - 1 7. Dynamical System- 1-order First-order...

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Unformatted text preview: 1 7. Dynamical System- 1-order First-order system: The differential equation is Solution: Take Laplace Transform: If u(t) is a unit step, ) t ( u ) t ( y dt ) t ( dy a = + 1 as ) s ( U ay ) s ( Y ) s ( U ) s ( Y ay ) s ( asY o o + + = = +- 1 as ay ) s ( Y s 1 o + + = 2 1-order systems (cont.) Let y o = 0, i.e. no initial condition then {} a t a 1 e 1 s 1 L L ) t ( y s 1 s 1 Y(s) a s 1 lim B , 1 1 as 1 lim A 1 as B s A ) 1 as ( s 1 ) s ( Y a 1 1 s 1 1 a 1 s s---- - = +- = +- = - = = = + = + + = + = 62.3% 1 y(t) t 3 1-order systems time constant The time-constant is defined as the time taken to reach the full value if the initial rate is maintained. Initial rate is Therefore the time to reach 1 takes a seconds; and at t = a And the time constant is a seconds. t dt dy = 63.2% i.e. , 632 . e 1 ) t ( y 1 =- =- a 1-e-1 1 y(t) t ( 29 a 1 t e e 1 dt d dt dy a t a t a 1 = = =- =-- 4 Dynamical Systems Behavior (2-order) We look at a single-degree-of- freedom (sdof) system first. Usually we represent this system by a spring-mass- damper system as shown. m c k x(t) f(t) The reason we call it sdof is: only one variable, i.e....
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This note was uploaded on 11/09/2009 for the course ENG 91301 taught by Professor Lui during the Spring '08 term at Hong Kong Institute of Vocational Education.

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lecture7 - 1 7. Dynamical System- 1-order First-order...

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