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Unformatted text preview: -4 (sample4) Calculations – Initial concentration of Fe 3+ = [Fe 3+ ] I = mL of [Fe (NO 3 ) 3 ] (x) .0020 M ` mL Total ` = [Fe 3+ ] I = 5 mL/10 mL (x) .0020 M ` = .001 Sample 1 Initial concentration of SCN = [SCN]- = mL of [KSCN] (x) .0020 M ` mL Total ` = 2 mL/10 mL (x) .0020 M ` = .0004 [FeSCN 2+ ] eq = A eq (x) [FeSCN 2+ ] std ` A std ` = .251/ 1.281 (x) .002 ` = 3.92e-4 Discussion – Egbuniwe Chinedum 3 From this experiment we can tell that the Initial concentration of Fe 3+ is .001. Because all of the quantities were 5 for this part the value is the same for all four samples. On the other hand SCN has four different quantities. The Initial concentration of SCN four all four samples are as follows: .0004, .0006, .0008, and .001. The equilibrium also has different values, in other words FeSCN 2+ eq is equal to 3.92e-4 , 5.65e-4 , 7.48e-4 , and 9.26e-4 for sample 1, 2, 3, and 4 respectively....
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This note was uploaded on 11/10/2009 for the course CHEM 107 taught by Professor Generalchemforeng during the Spring '07 term at Texas A&M.
- Spring '07