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# lab2 - 26 is twice as common as the next most common value...

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Alexandra Linder MATH 1710 Th 1:25 PM Lab 2 1. a. This is a Bernoulli trial because there are only two possible outcomes-success or failure. b. n= 50 chips tested per experiment p= .9 (probability that the chips will work perfectly) x= the number of chips that work perfectly if we test 50 of them c. d. This histogram is unimodal and asymmetrical. The range is 39-49. 2. a. n= 40 people tested p= .6 (probability they will be cured) x= the number of people cured by the old treatment This histogram is also unimodal, but there are a few differences from the one above. The range is a bit larger and so is the standard deviation. Also, the most common value here,

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Unformatted text preview: 26, is twice as common as the next most common value. Above, the most common value only occurs one more time than the next most common values. b. The new medication should cure at least 30 people to be more effective than before. 3. Another situation in which there are Bernoulli trials would be a random trial to see how many people's eyes out of 100 will be blue or not blue. The possible eye colors are blue, brown, hazel, and green. So n=100 people, p=.25 (probability of blue) and X=the number of people with blue eyes. The histogram resulting from this binomial distribution will be unimodal and asymmetrical....
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lab2 - 26 is twice as common as the next most common value...

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