lab5 - Sampling distributions Case I 1. In Ticks 1, 4 ticks...

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Sampling distributions Case I 1. In Ticks 1, 4 ticks have lyme disease, which is 20% of the sample- ˆp=.2 The entire population probably does not have the exact same percentage of infected ticks because this relatively small sample. This histogram is unimodal and skewed to the left. The median is .15 and the mean is .145. This distribution indicates that in a sample size of 20, the proportion of infected ticks will be between 0 and .25. 2. This distribution is unimodal and skewed to the right. The mean and median are smaller than above with the smaller sample, as are the standard deviation and IQR. 3.

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around .1 which means that there is an average of 10% infestation in the entire population. Case II 1. This histogram is unimodal and skewed to the right. There is an outlier around 45,000. The median cost was \$8,445, but the range is very large. There were 12,145 patients and the mean cost was \$9879.09. 2. n=24.29, the mean is 10326.2 which is a bit higher than the actual mean, but the
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This note was uploaded on 11/11/2009 for the course MATH 1710 taught by Professor Staff during the Fall '08 term at Cornell.

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lab5 - Sampling distributions Case I 1. In Ticks 1, 4 ticks...

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